Answer:
Step-by-step explanation:
Given that the bivariate distribution of X and Y is described below:
x 1 2
y
1 0.21 0.14 0.35
0 0.47 0.18 0.65
Pdf of Y is
Y 1 0
p 0.68 0.32
C) Pdf of X is
x 1 2
p 0.35 0.65
Mean of X =
Var(x) = E(x^2)-Mean ^2 =
C) Mean of Y = 1(0.68)+0 = 0.68
Var(y) = 1(0.68)-0.68^2
= 0.2176