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2 years ago

7

F(x) = 3 x² + 5 x - 7 and g(x) = x² + 8 x + 10

1 answer:

Korolek [52]2 years ago

8 0

$f(x) + g(x) \\ 3x {}^{2} + 5x - 7 + x {}^{2} + 8x + 10 \\ 4x {}^{2} + 13x + 3$

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What is the simplified form of the quantity of x plus 7, all over the quantity of x plus 3 + the quantity of x minus 4, all over

allochka39001 [22]

$\frac{3x + 21}{4x + 5}$

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3 years ago

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mamaluj [8]

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3 years ago

Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from B, a distance o

g100num [7]

Answer:

The value is $k =109.6 \ miles$

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

The distance from city A to B is AB = 467.3 miles

The bearing from B to C is $\theta_{BC} = N 28.7E$

The bearing from B to A is $\theta_{BA} = N 60.7E$

The bearing from A to B is $\theta_{AB} = S60.7W$

The bearing from A to C is $\theta_{AC} = S79.1W$

Generally from the diagram

$\theta_A = 180 - 60.7 -79.1$

=> $\theta_A = 40.2 ^o$

Also

$\theta_B = 32^o$

and

$\theta_C = 180 - (\theta_A +\theta_B )$

=> $\theta_C = 180 - (40.2 + 32 )$

=> $\theta_C = 107.8 ^o$

Generally according to Sine Rule

$\frac{BC}{sin (\theta_A)} = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}$

=> $\frac{BC}{sin (40.2)} = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}$

So

$\frac{BC}{sin (40.2)} = \frac{467.3 }{sin (107.8)}$

=> $BC = 316.8 \ miles$

Also

$\frac{CA}{sin (32)} = \frac{467.3 }{sin (107.8)}$

$CA = 260 .1 \ miles$

Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct flight is mathematically represented as

$k = [CA +BC] - AB$

=> $k = [260 .1 +316.8]- 467.3$

=> $k =109.6 \ miles$

4 0

3 years ago

The ratio of the number of dogs the number of cats is 4:5. There are 270 animals on the rescue Farm. The number of dogs is 4/5.

mafiozo [28]

Answer:

<em>Here is the complete question:</em>

The ratio of the number of dogs to the number of cats is 4:5. There are 270 animals on the rescue farm. for each of the following statements, explain whether statements is true or false and why:

a. The number of dogs is 4/5 the number of cats.

b. 4/5 of the pets at the farm are dogs.

c. There are exactly 30 more cats than dogs.

d. There are exactly 30 dogs at the farm.

e. 5/9 of the pets at the farm are cats.

a,c and e are true statements.

Step-by-step explanation:

Let the number of dogs be "d' and number of cats be "c".

According to the question:

⇒ $c+d=270$ ...equation (i)

Arranging the ratio:

⇒ $\frac{4}{5} = \frac{d}{c}$

⇒ $4c=5d$

⇒ $c=(\frac{5}{4})d$ ...equation (ii)

Plugging (ii) in equation (i).

⇒ $c+d=270$

⇒ $\frac{5}{4} d+d=270$

⇒ $\frac{5d+4d}{4} =270$

⇒ $9d=270\times 4$

⇒ $d=\frac{270\times 4}{9}$

⇒ $d=120$

Number of dogs "d" = 120

Number of cats "c" = (270-120) = 150

Lets check each statement:

a.

The number of dogs is 4/5 the number of cats.

⇒ $\frac{4}{5} \times 150$

⇒ $\frac{4\times 150}{5}$

⇒ $120$

Statement is true.

b.

4/5 of the pets at the farm are dogs.

⇒ $\frac{4}{5} \times 270$

⇒ $216$

Number of dogs = 120

So the above statement is false.

c.

There are exactly 30 more cats than dogs.

⇒ $c-d =30$

⇒ $150-120=30$

Statement is true.

d.

There are exactly 30 dogs at the farm.

False, as there are 120 dogs

e.

5/9 of the pets at the farm are cats.

⇒ $\frac{5}{9} \times 270$

⇒ $150$

Statement is true.

So,

Statement a,c and e are true as we could observe in the explanation.

8 0

2 years ago

5+3x write in verbal expression

Keith_Richards [23]

Answer:

Five plus free equals 7

Step-by-step explanation:

I added five plus three

5 0

2 years ago

Read 2 more answers