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Scrat [10]
3 years ago
7

F(x) = 3 x² + 5 x - 7 and g(x) = x² + 8 x + 10

Mathematics
1 answer:
Korolek [52]3 years ago
8 0

f(x) + g(x) \\ 3x {}^{2}  + 5x - 7 + x {}^{2}  + 8x + 10 \\ 4x {}^{2}  + 13x + 3

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4(3xy^4)^3/(2x^3y^5)^4
myrzilka [38]

Answer:

\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}=\frac{27}{4x^9y^8}

Step-by-step explanation:

Given the expression

\:\:\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}

solving the expression

\:\:\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}=4\cdot \:\frac{\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}

             =4\:\frac{27x^3y^{12}}{16x^{12}y^{20}}

              =4\cdot \frac{3^3}{2^4x^9y^8}

The multiply fractions are defined as

\:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

so the expression becomes

                =\frac{3^3\cdot \:4}{2^4x^9y^8}

                =\frac{3^3\cdot \:2^2}{2^4x^9y^8}

                =\frac{3^3}{2^2x^9y^8}

Refining

                 =\frac{27}{4x^9y^8}

Therefore,

\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}=\frac{27}{4x^9y^8}            

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