Answer:
Step-by-step explanation:
m∠ JHI + m∠GHJ = 180 { linear pair}
m∠JHI + 90 = 180
m∠JHI = 180 -90 = 90
In ΔGHJ and ΔJHI,
GJ = IJ { given}
JH = JH {common}
m∠ JHI = m∠GHJ { above proved}
ΔGHJ ≅ ΔJHI { Angle Side Side congruence}
Answer:
steps below
Step-by-step explanation:
To construct tangent line to a circle based on two main properties of tangent line and inscriber triangle of circle
1. A line is tangent to a circle when it intersects the circle in one point. At that point, the radius of the circle forms a right angle with the tangent line. If the radius forms a right angle with the tangent line, <u>then the segment OP becomes the hypotenuse of the right triangle.</u>
2. a triangle inscribed in a circle having a diameter (OT) as one side is a right triangle.
Construction:
1. connect P and circle center "O"
2. construct perpendicular bisector of PO --- AB, Intersect M will be the center of new circle and its radius is MP
3. With the center of "M" and radius MP: construct a circle and intersect original circle at "T" and "T'"
4. PT and PT' are the tangent lines
5 1/2 - 3 1/4
11/2 - 13/4
22/4 - 13/4 = 9/4
your answer is 2 1/4
hope this helps
The blue line (B)
You can count by going up 2 over 1
Answer:
2 × 2 × 2 × 2 × 3, or
×3.