Answer:
3 1/3 gallons per minute
Step-by-step explanation:
We can use ratio's to solve this problem. We will put gallons on top and time on the bottom
5/6 gallons x gallons
-------------------- = -------------
1/4 minute 1 minute
Using cross products
5/6*1 = 1/4 x
Multiply by 4 on each side
5/6 * 4 = 1/4 *4 x
20/6 = x
Dividing the top and bottom by 2
10/3 =x
Changing this back to a mixed number
3 goes into 10 3 times with 1 left over
3 1/3 gallons per minute
Cos (π/2 - x) = sin x = 3/5
tan x = sin x / cos x = 3/5 / 4/5 = 3/4
csc x = 1/sin x = 1 / 3/5 = 5/3
sec x = 1/cos x = 1 / 4/5 = 5/4
cot x = 1/tan x = 1 / 3/4 = 4/3.
Where is q? What should i do?
Isolate the x. Subtract 5/8 from both sides
x + 5/8 (-5/8) = 6 (-5/8)
x = 5 8/8 - 5/8
Simplify
x = 5 3/8 is your answer
hope this helps
1.5, 2
When reflecting across the y-axis, the y in (x, y) stays the same but the x's sign is changed to the opposite.