Answer:
The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 27 - 1 = 26
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.0518
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
In this question:
. So


The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.
Answer:
See below
Step-by-step explanation:
The ratio of the secants is the same when set up as full length to external length.
Formula
MN/LN = QN/PN
Givens
LN = 22 + 14 = 36
MN = 14
PN = 32
QN = x
Solution
14/36 = x / (32) Multiply both sides by 32
14*32 / 36 = x Combine 14 and 32
448/36 = x Divide by 36 and switch
x = 12.4
Answers
PN (External) = 13 is the closest answer
Length LN = 36
Answer:
y = 2
Step-by-step explanation:
varies inversely
xy = k
y = 7 when x = 2/3
(2/3)7 = k
14/3 = k
k = 14/3
--------------------
find y when x = 7/3
(7/3)y = 14/3
multiply both sides by 3/7
y = 14/3 * 3/7
y = 2