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4 years ago

Suppose cos(π/2−x) =3/5, cos x =4/5 find sin, tan, csc, sec, cot

1 answer:

5 0

Cos (π/2 - x) = sin x = 3/5
tan x = sin x / cos x = 3/5 / 4/5 = 3/4
csc x = 1/sin x = 1 / 3/5 = 5/3
sec x = 1/cos x = 1 / 4/5 = 5/4
cot x = 1/tan x = 1 / 3/4 = 4/3.

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Radius<br> Diameter: 26 inches<br> Circunference :<br> Area:

kicyunya [14]

Answer:

Radius is 13

Circumference = 26π

Area is 169π

Step-by-step explanation:

use the radius, circumference, and area formulas.

Radius is 13

Circumference = 26π

Area is 169π

substitute pi for 3.14, 3, etc if needed

8 0

3 years ago

I have to find two points for this eqaution.. x+1=0

lisov135 [29]

I think there is only one point x = -1.

Are you sure it's not x^2 + 1 = 0, if you had this equation the two points will be -1 and 1.

Or the equation was something like: x+1 =y?

If the equation is x+1=y.

First point: (-1,0)

Second point: (0,1)

//Hope this is what you are looking for. Sorry if it's incorrect.

3 0

3 years ago

What expression is equivalent to -1/3(6x+15)-3

Anna11 [10]

Answer:

$\large\boxed{-\dfrac{1}{3}(6x+15)-3=-2x-8}$

Step-by-step explanation:

$-\dfrac{1}{3}(6x+15)-3\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=\left(-\dfrac{1}{3}\right)(6x)+\left(-\dfrac{1}{3}\right)(15)-3\\\\=-2x-5-3\\\\=-2x-8$

5 0

4 years ago

A pound of chocolate costs 7 dollars. Joe buys p pounds. Write an equation to represent the total cost c that Joe pays.

pickupchik [31]

Answer:

Total cost, c = 7p

Step-by-step explanation:

1pound =$7

Joe buys p pounds,

p pounds = $7 * p

p pounds = 7p

3 0

3 years ago

One positive number is 5 times another number . The difference between the two numbers is 80, Find the numbers.

nika2105 [10]

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Define the numbers:
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Let x be one number.
One number = x
Other number = 5x

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Construct the equation:
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5x - x = 80

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Combine like terms:
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4x = 80

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Divide by 4 on both sides:
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x = 20

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Find the 2 numbers:
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One number = x = 20
Other number = 5x = 5(20) = 100

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Answer: The two numbers in increasing order are 20 and 100.
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4 0

3 years ago