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3 years ago

Easy questions! I will give brainliest! Tysm!

Mathematics

1 answer:

ziro4ka [17]3 years ago

4 0

Answer:

Step-by-step explanation:

area square = side²

(3/5)²

√(1/16)

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The sum of two consecutive integers is 91. Find the integers.

Reil [10]

Answer:

Let the smaller integer be x and greater integer be (x+1)

x+(x+1)=91

2x+1=91

2x=91-1=90

x=90/2

x=45

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2 years ago

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∆ABC m∠B = 90° AB = 4 BC = 3<br> Find AC

lutik1710 [3]

Step-by-step explanation:

In ∆ABC, m∠B = 90°

Therefore ∆ABC is a right angled triangle with sides AB = 4 & BC = 3. AC is the hypotenuse.

Hence, by Pythagoras theorem:

$AC^2 = AB^2 +BC^2 \\ \\ \therefore \: AC = \sqrt{AB^2 +BC^2 } \\ = \sqrt{ {4}^{2} + {3}^{2} } \\ = \sqrt{16 + 9} \\ = \sqrt{25} \\ = 5 \\ \\ \huge \red{ \boxed{ \therefore \: AC = 5 \: units}}$

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3 years ago

The Movie Haven is planning to order new medium-size popcorn containers. It has a choice of four different containers. It costs

murzikaleks [220]

Answer:

the answer is container c

b=11.14in2

12in

Step-by-step explanation:

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3 years ago

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You buy halibut at $25 per pound.one portion of seared halibut requires 6 ounces of halibut.how much does the halibut for one po

Minchanka [31]

Answer:

$9.38

Step-by-step explanation:

halibut is measured in pounds and a portion is measured in ounces

in order to determine the cost, the two units have to be comparable. So, ounces have to be converted to pounds

1 ounce = 0.0625 pounds

6 ounces = 0.0625 x 6 = 0.375 pounds

0.375 pounds would cost 0.375 pounds x 25 pounds = $9.38

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3 years ago

What are the solutions to x3=5−5i in polar form

asambeis [7]

Answer:

$z_1=(5\sqrt{2})^{1/3}cis(\frac{7\pi}{12})$

Step-by-step explanation:

To find the roots of the complex number you use the following formula:

$z=re^{i\theta}\\\\z_k= (r)^{1/n}[cos(\frac{\theta+2\pi k}{n})+sin(\frac{\theta+2\pi k}{n})];\ \ k=0,1,2..n-1$ (1)

in this case the polar number in polar form is:

$r=\sqrt{5^2+5^2}=5\sqrt{2}\\\\\theta=tan^{-1}(\frac{-5}{5})=-45\°$

By replacing in (1) you obtain:

$z_0=(5\sqrt{2})^{1/3}cis(\frac{-\pi/4+0}{3})\\\\z_1=(5\sqrt{2})^{1/3}cis(\frac{-\pi/4+2\pi}{3})=(5\sqrt{2})^{1/3}cis(\frac{7\pi}{12})\\\\z_2=(5\sqrt{2})^{1/3}cis(\frac{-\pi/4+4\pi}{3})=(5\sqrt{2})^{1/3}cis(\frac{15\pi}{12})$

hence, you have:

h. 52‾√3cis(7π12)

7 0

3 years ago