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klio [65]
3 years ago
5

What is the main purpose of being on offense

Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0
B to defend your goal
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765ab4 is divisible by 36. Compute all ordered pairs (a, b) for which this is possible
tia_tia [17]

Answer:

All the ordered pairs (a,b) are

(0,5), (2,3), (4,1), (6,8), and (8,6).

Step-by-step explanation:

765ab4 to be divisible by 36, it must be divisible by both 9 and 4.

For any number to be divisible by 4, the last two digits of the number must be divisible by 4.

Here, the last two digits are b4, so as the number b4 is divisible by 4, b can be 0,2,4,6, and 8.

For any number to be divisible by 9, the sum of all the digit of the number must be divisible by 9.

Here, the sum of all the digits, S= 7+6+5+a+b+4=22+a+b.

Now, we have b={0,2,4,6, 8}

For b=0,

S=22+a+0=22+a which is a multiple of 9.

So, the possible value of the digit a :

a=5

So, (a,b)=(0,5)

For b=2,

S=22+a+2=24+a which is a multiple of 9.

So, the possible value of the digit a :

a=3

So, (a,b)=(2,3)

For b=4,

S=22+a+4=26+a which is a multiple of 9.

So, the possible value of the digit a :

a=1

So, (a,b)=(4,1)

For b=6,

S=22+a+6=28+a which is a multiple of 9.

So, the possible value of the digit a :

a=8

So, (a,b)=(6,8)

For b=8,

S=22+a+8=30+a which is a multiple of 9.

So, the possible value of the digit a :

a=6

So, (a,b)=(8,6)

Hence, all the ordered pairs (a,b) are

(0,5), (2,3), (4,1), (6,8), and (8,6).

3 0
3 years ago
What is the volume of a square prism with a base area of 25 square centimeters and a height of 6 centimeters?
bonufazy [111]

Answer:

since, v=a(square) ×h

Step-by-step explanation:

v=a(squate)cm×hcm

v=25(square)cm×6cm

v=625cm×6ccm

v=3,750cm(cube)

7 0
3 years ago
Please help me! Pic included! ;) :p
saul85 [17]
Here you go!! Hope it helps !!

5 0
3 years ago
1 6 36 216 what come next
baherus [9]
The answer will be 346
8 0
3 years ago
Read 2 more answers
Ln how many ways 5 person sitted in a round table having 8 seats?
kvasek [131]

Answer: First consider the case that ‘just’ 5 persons are seated around a round table.

Clearly, ‘just’ 5 persons can be seated around a round table in (5 - 1)! = 4! = 24 ways.

Now, one vacant chair is to be inserted among them.

Say, for a particular sitting arrangement ‘ABCDE’; there are 5 scopes available for inserting the vacant chair - between A and B, between B and C, between C and D, between D and E & between E and A.

So, there are 5*24 = 120 ways available that 5 persons can sit around a round table with 6 chairs.

Step-by-step explanation:

First consider the case that ‘just’ 5 persons are seated around a round table.

Clearly, ‘just’ 5 persons can be seated around a round table in (5 - 1)! = 4! = 24 ways.

Now, one vacant chair is to be inserted among them.

Say, for a particular sitting arrangement ‘ABCDE’; there are 5 scopes available for inserting the vacant chair - between A and B, between B and C, between C and D, between D and E & between E and A.

So, there are 5*24 = 120 ways available that 5 persons can sit around a round table with 6 chairs.

5 0
3 years ago
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