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son4ous [18]
3 years ago
6

How does stress affects rocks

Mathematics
1 answer:
Furkat [3]3 years ago
8 0
By the environment, the sun, the temperature, push, pulling
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Simplify:(4x2 - 2x) - (-5x2 - 8x)
Marysya12 [62]

Answer:

4x2+5x2-2x+8x=9x2+6x

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A painter uses 2.75 gallons of paint per hour. How many gallons of paint will the painter use in 3.5 hours?
anygoal [31]

Answer:

9.625 gallons will be used by the painters in 3.5 hours

Step-by-step explanation:

2.75 gallons = 1 hr

X gallons = 3.5 hrs

X = (3.5 × 2.75)/1

X = 9.625 gallons

9.625 gallons will be used by the painters in 3.5 hours

8 0
3 years ago
Read 2 more answers
4. The length of Marshall’s rectangular poster is 2 times its width. If the perimeter is 24 inches, what is the area of the post
lubasha [3.4K]
The length is 7 with a width of 5, so the area is 35
3 0
3 years ago
Find the Equation of x(2x+5)-3(2x+5)=0
Nata [24]
2x² + 5x -6x - 15 = 0

2x² - x - 15 = 0

2x² -x = 15

x = 3

3 x 3 = 9 x 2 = 18 - 3 = 15

i really don't know how i got 3 in the first place but that is your answer

hope this helps


5 0
3 years ago
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
Read 2 more answers
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