120 personas con bronquitis y fumadores, 15 con bronquitis y no fuman, 42 sanos y fumadores, 65 sanos y no fumadores. Si se elig
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As the variation is direct we have:
We must find the value of k.
For this, we use the following data:
y = 200 when x = 5
Substituting values we have:
Clearing k:
Then, the function is:
We evaluate the function for x = -3
Answer:
the value of y when x = -3 is:
c.
72
We must find the value of k.
For this, we use the following data:
y = 200 when x = 5
Substituting values we have:
Clearing k:
Then, the function is:
We evaluate the function for x = -3
Answer:
the value of y when x = -3 is:
c.
72
I think you meant to say
(as opposed to <em>x</em> approaching 2)
Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:
Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2: