Find x, use pic for more info

Consider a circle whose size can vary. The circumference of the circle is always 2 π 2π times as large as its radius. Let r r re

Alenkasestr [34]

Answer: $C=2\pi r$

Step-by-step explanation:

Let be "C" the circumference of the circle (in feet) and "r" the radius of the circle (in feet).

Based on the information provided in the problem, you know that the circumference of the circle is always $2\pi$ as large as its radius.

Notice that this indicates a multiplication. Then, this means that the circumference of the circle is always equal to $2\pi$ by "r".

Based on this, you can write the following formula that expresses the circumference "C" in terms of the radius "r":

$C=2\pi r$

4 0

3 years ago

PLEASE HURRY! What is the rate of change of the function? -2 - 1/2 1/2 2 Thank you.

svetlana [45]

Answer: -2

Step-by-step explanation: The line has a slope of -2/1, which is just -2.

6 0

3 years ago

Read 2 more answers

Which equation represents the graph below? A. y=3x-2 B.y=-2x+3 C.y=3x-2 D.2x+3

KatRina [158]

Answer:

d

Step-by-step explanation:

5 0

3 years ago

The function f(x) = 4(4)x represents the growth of a fly population every year in a remote swamp. Jackie wants to manipulate the

Sauron [17]

The function f(x) = 4(4)x represents the growth of a fly population every year in a remote swamp.

calculates three times a year, not just once a year.

$f(x)= 4(4)^x$

3 times a year

so x becomes 3x

$f(x)= 4(1+r)^{3x}$

$4(4)^x=4(1+r)^{3x}$

Take log on both sides

$log(4)^x=log(1+r)^{3x}$

Use log property and move exponent before log

$xlog(4)=3xlog(1+r)}$

Divide both sides by x

log 4 = 3 log(1+r)

Solve for '1+r'

log 4 = log(1+r)^3

Remove log from both sides

4 = (1+r)^3

take cube root on both sides

1.584740= 1+r

1+r = 1.59

$f(x)= 4(1+r)^{3x}$

so equation becomes

$f(x)= 4(1.59)^{3x}$

1+r = 1.59

subtract 1 from both sides

So r= 59 = 59%

So growth factor is 59%

Answer is option C

5 0

3 years ago

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

4 0

4 years ago