Answer:
The probability of getting two consumers comfortable with drones is 0.3424.
Step-by-step explanation:
The probability that a consumer is comfortable having drones deliver their purchases is, <em>p</em> = 0.43.
A random sample of <em>n</em> = 5 consumers are selected, and exactly <em>x</em> = 2 of them are comfortable with the drones.
To compute the probability of getting two consumers comfortable with drones followed by three consumers not comfortable, we will use the Binomial distribution instead of the multiplication rule to find the probability.
This is because in this case we need to compute the number of possible combinations of two consumers who are comfortable with drones.
So, <em>X</em> = number of consumers comfortable with drones, follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.43.
Compute the probability of getting two consumers comfortable with drones as follows:
Thus, the probability of getting two consumers comfortable with drones is 0.3424.
Two events are said to be Disjoint or Mutually Exclusive if the two events can not happen at the same time.For example when we throw a die getting an even number is disjoint to getting an odd number.
I.e Probability(A∩B)=0
Let me explain this concept through venn diagram.
Pr[A∪B]=0.7, Pr[A]=0.25
Since events are Disjoint
Pr[A∩B]=0
Pr[A∪B]=Pr[A] + Pr[B]
0.7=0.25 +Pr[B]
0.7-0.25=Pr[B]
⇒Pr[B]=0.45=45/100=9/20
Now events are said to be independent if Pr[A and B]=Pr[A] ×Pr[B]
Events are said to be independent if occurrence of one is not affected by occurrence of other.For example getting multiple of 2 as one event and getting multiple of 3 as second event when we throw a die.
Pr[A∪B]=0.7, Pr[A]=0.25
Pr[A∪B]= Pr[A]+ Pr[B]-Pr[A∩B]
But Pr[A∩B]= Pr[A] ×Pr[B]
⇒Pr[A∪B]= Pr[A]+ Pr[B]- Pr[A] ×Pr[B]
⇒0.7=0.25+p-0.25×p
⇒0.7-0.25=p- 0.25 p
⇒0.45=0.75 p
⇒p= 0.45/0.75
⇒p =3/5
I think the answer is 27/4
Numerator:
7(3)-3(-2)= 21+6= 27
Denominator
2(3) +y
6+(-2)= 4
Answer in total
27/4
I hope that’s right