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3 years ago

URGENTTTTTTT 20PT.

Mathematics

2 answers:

disa [49]3 years ago

7 0

Answer:

the answers are C,D, and E........

Step-by-step explanation:

zaharov [31]3 years ago

4 0

Out of the choices provided the answers would be C,D, and E
She has four choices for the first brother's towel and three choices for the second brother's towel
ABC,ABD,ABE,ACD,ACE, and ADE are the possible outcomes.
If Fiona did not choose towel A for herself, there would be more outcomes.
Hope this helps!

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Ms. Smith and Mr. Roberts are running a race. Ms. Smith runs 8, 305 feet. Mr. Roberts runs 2 miles. How many feet further does M

Tcecarenko [31]

Answer:

Mr. Roberts runs 2,255 more feet then Ms. Smith.

Step-by-step explanation:

So I took 5,280 + 5,280 = 10,560 so now I can just take Ms. Smith's 8,305 and subtract it from 10,560 which gave me 2,255 so Mr. Roberts runs 2,255 more feet then Ms. Smith.

3 0

3 years ago

Given LaTeX: f\left(x\right)=x^{^3}-3x+4f ( x ) = x 3 − 3 x + 4, determine the intervals where the function is increasing and wh

Vedmedyk [2.9K]

Answer:

Increasing: $x$ and $x>1$ .

Decreasing: $-1$

Step-by-step explanation:

We have been given a function $f(x)=x^3-3x+4$ . We are asked to determine the intervals, where the function is increasing and where it is decreasing.

First of all, we will find critical points of our given function by equating derivative of our given function to 0.

Let us find derivative of our given function.

$f'(x)=\frac{d}{dx}(x^3)-\frac{d}{dx}(3x)+\frac{d}{dx}(4)$

$f'(x)=3x^{3-1}-3+0$

$f'(x)=3x^{2}-3$

Let us equate derivative with 0 as find critical points as:

$0=3x^{2}-3$

$3x^{2}=3$

Divide both sides by 3:

$x^{2}=1$

Now we will take square-root of both sides as:

$\sqrt{x^{2}}=\pm\sqrt{1}$

$x=\pm 1$

$x=-1,1$

We know that these critical points will divide number line into three intervals. One from negative infinity to -1, 2nd -1 to 1 and 3rd 1 to positive infinity.

Now we will check one number from each interval. If derivative of the point is greater than 0, then function is increasing, if derivative of the point is less than 0, then function is decreasing.

We will check -2 from our 1st interval.

$f'(-2)=3(-2)^{2}-3=3(4)-3=12-3=9$

Since 9 is greater than 0, therefore, function is increasing on interval $(-\infty, -1) \text{ or } x$ .

Now we will check 0 for 2nd interval.

$f'(0)=3(0)^{2}-3=0-3=-3$

Since -3 is less than 0, therefore, function is decreasing on interval $(-1,1) \text{ or } -1$ .

We will check 2 from our 3rd interval.

$f'(2)=3(2)^{2}-3=3(4)-3=12-3=9$

Since 9 is greater than 0, therefore, function is increasing on interval $(1,\infty) \text{ or } x>1$ .

6 0

3 years ago

Given the line below. Write the point-slope form of the given line that passes through the points (0, 3) and (4, 0). Identify (x

jeka57 [31]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~{{ 0}} &,&{{ 3}}~) 
% (c,d)
&&(~{{4}} &,&{{ 0}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{0-3}{4-0}\implies -\cfrac{3}{4}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-3=-\cfrac{3}{4}(x-0)$

4 0

3 years ago

Determine the slope of the line that contains the given points. E(-5,6), (4, -3) *

S_A_V [24]

Answer:

-1

Step-by-step explanation:

Use the slope formula to calculate

-3-6/4-(-5)

= -9/9

= -1 (Slope)

8 0

2 years ago

A number a is to the left of the number b on the number line how do the numbers -a and -b compare?

Leokris [45]

Answer:

-a will be greater than -b because for example, when a=2 and b=5, -a=-2 and -b=-5

8 0

2 years ago