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kumpel [21]
3 years ago
14

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided. The vertical left edge

of a trapezoid is 8 inches and meets the bottom edge of the trapezoid at a right angle. The bottom edge is 4 inches and meets the vertical right edge at a right angle. The right edge is 11 inches. The top slanted edge measures 5 in Calculate the area of the trapezoid, which is not drawn to scale
Mathematics
1 answer:
Mama L [17]3 years ago
7 0

The area of the given trapezoid is 38 in².

<h3>What is a trapezoid?</h3>

A trapezoid is a quadrilateral (has four sides and four angles) with a single pair of parallel sides. The area (A) of a trapezoid is given by:

A = (1/2) * (a + b) * h

Where a, b are the parallel sides and h is the height of the trapezoid.

Given that a = 8, b = 11, h = 4, hence:

A = (1/2) * (8 + 11) * 4 = 38 in²

The area of the given trapezoid is 38 in².

Find out more on trapezoid at: brainly.com/question/1410008

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Answer:

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Step-by-step explanation:

Here, the given function is:f(x)=   \frac{9-x^2}{x^2-4}

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We get:

<u>a. (-infinity, -3) </u>

put k = -4 from the given interval

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d. (2, 3)

put k =2.5 from the given interval

We get f(2.5)=   \frac{9-(2.5)^2}{(2.5)^2-4}  = \frac{9-6.25}{6.25-4}  = \frac{2.75}{2.25}  > 0

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e. (infinity, 3)

put k = 4 from the given interval

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⇒ f (x) < 0 for x ∈ (3,∞)

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