All categories

2 years ago

A car drives with a constant speed of 56 km/h. How far can it travel in 1 hour?

Mathematics

2 answers:

Rama09 [41]2 years ago

5 0

Answer:

56km

Step-by-step explanation:

I got 56km because the car drives at a constant speed of 56 km/h. So, in one hour the car can travel 56km.

Therefore, the car can travel 56km in 1 hour.

Alborosie2 years ago

4 0

Answer:

56 kilometers

Step-by-step explanation:

The answer is in the question it travels 56 km/h this means every one hour the car goes 56 km

You might be interested in

1/4,1/12,1/36,1/108 Describe the pattern for the sequence. Then find the next three terms

lidiya [134]

The number is multiplied by 3 every time

and next three terms are 1/324, 1/972 and 1/2916

good luck

3 0

2 years ago

2. Find the lateral area and surface area of the prism. 4 cm 5 cm 4 cm 3 cm

Vaselesa [24]

Answer:

Lateral = 48 cm squared and Surface area = 60 cm squared

Step-by-step explanation:

Lateral surface area = 4 x 4 + 5x4( Slope) + 4 x 3 (Cross section x2) = 48

Surface area: Lateral + 4x3(base)

4 0

2 years ago

Jessica has two strings. the first string measures 80 cm and the second string measures 64cm. she wants to cut the strings into

omeli [17]

The highest common denominator between 80 and 64 is 16. This means no string can be cut longer than 16 inches for them all to have the same length.

5 0

3 years ago

What would be the second step in solving the equation y−16=3y?

stiv31 [10]

Answer:

Divide both sides by 4

Step-by-step explanation:

Please give brainliest

3 0

2 years ago

Read 2 more answers

What is the distance between the points (2,10) and (-6, 4) on the coordinate

stellarik [79]

Answer:

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

Therefore distance s=10 units

Step-by-step explanation:

Given points are (2,10) and (-6, 4) on the coordinate plane

To distance between the given points :

The distance formula is $s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ units

Let $(x_1,y_1)$ , $(x_2,y_2)$ be the given points (2,10) and (-6, 4) respectively

Now substituting the values in the distance formula we get

$s=\sqrt{(-6-2)^2+(4-10)^2}$

$=\sqrt{(-8)^2+(-6)^2}$

$=\sqrt{8^2+6^2}$

$=\sqrt{64+36}$

$=\sqrt{100}$

$=10$

Therefore s=10 units

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

5 0

3 years ago