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Marina CMI [18]
3 years ago
8

Please solve 13 < m –25

Mathematics
2 answers:
Nadya [2.5K]3 years ago
5 0

Answer:

m (is greater than) 38

Step-by-step explanation:

bruh

Veseljchak [2.6K]3 years ago
3 0

Answer:

M<33

\

broski chillin with that fortnite flow

Step-by-step explanation:

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A new car is purchased for 24600 dollars. The value of the car depreciates at 5.5% per year. To the nearest year, how long will
boyakko [2]

Answer:

The number of years until the value of the car is 11300 dollars is 9 years.

Step-by-step explanation:

This can be calculated using the following formula:

Value of the Car = Purchase cost - (Annual depreciation expenses * N) ........ (1)

Where;

N = Number of years until the value of the car is 11300 dollars

Purchase cost = $24,600

Annual depreciation rate = 5.5%

Annual depreciation expenses = $24,600 * 5.5% = $1,353

Value of the car = $11,300

Substituting the value into equation (1) and solve for N, we have:

$11,300 = $24,000 - ($1,353 * N)

$1,353 * N = $24,000 - $11,300

$1,353 * N = $12,700

N = $12,700 / $1,353

N = 9.38654841093865

Rounding to the nearest year as required by the question, we have:

N = 9

Therefore, the number of years until the value of the car is 11300 dollars is 9 years.

Step-by-step explanation:

4 0
3 years ago
Please Help !!!
solong [7]
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)

moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g


Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05

N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
5 0
4 years ago
-2p + 7= 11 i need a answer know pleas help me
siniylev [52]

Answer:

p= -3/2 or p= -1 1/2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
At any point in time, there could be bicycles, tricycles, and
Aleksandr-060686 [28]

Answer:

There may be 1 or 3 tricycles in the parking lot.

Step-by-step explanation:

Since at any point in time, there could be bicycles, tricycles, and cars in the school parking lot, and today, there are 53 wheels in total, if there are 15 bicycles, tricycles, and cars in total, to determine how many tricycles could be in the parking lot, the following calculation must be performed:

13 x 4 + 1 x 3 + 1 x 2 = 57

11 x 4 + 1 x 3 + 3 x 2 = 53

10 x 4 + 3 x 3 + 2 x 2 = 53

8 x 4 + 5 x 3 + 2 x 2 = 51

10 x 2 + 1 x 3 + 4 x 4 = 39

9 x 3 + 1 x 2 + 5 x 4 = 49

Therefore, there may be 1 or 3 tricycles in the parking lot.

6 0
3 years ago
NEED HELP HURRY
Serga [27]

Answer:

6.3+1.1

Step-by-step explanation:

The communitive property of addition states that no matter what order of the numerical values the answer will be the same. hope this helps

8 0
3 years ago
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