Question

find the number of running and passing plays using substitution method 110 plays 3 yards per run 7 yards per pass total yards 378

Answer 1

Let x be the number of running plays

Y  be the number of passing plays

Since the total plays is 110

 X + y = 110

And total yard is 378

3x + 7y = 378

Using the first equation

X = 110 – y and substitute to the 2nd equation

3(110 – y) + 7y = 378

And solve for y

Y = 12

Substitute to eqution 1

X = 110 – 12 = 98