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Annette [7]
3 years ago
13

Please help me with this question

Mathematics
2 answers:
butalik [34]3 years ago
8 0
You would have to divide first then multiply and get 28
torisob [31]3 years ago
4 0

Answer:

-4x-7

Step-by-step explanation:

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How many ways are there to rearrange the letters ALIVE in such a way that the word EVIL is not contained in the resulting word
Sergio [31]

Answer: 118 combinations.

Step-by-step explanation:

In ALIVE we have 5 letters, rearranging it we have the possible options of:

5 options for the first letter.

4 options for the second letter, as one was already chosen for the first one

3 options for the third letter, as 2 were already chosen.

2 options for the fourth letter.

1 option for the last letter.

The total number of combinations will be equal to the product of the numbers of options for each letter, then we have:

5*4*3*2*1 = 120 combinations.

And the combinations where the word EVIL is formed are:

AEVIL

EVILA

2 combinations, then the total number of combinations such that the word evil is not formed are:

120 - 2 = 118 combinations.

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3 years ago
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Answer:

a b c

Step-by-step explanation:

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exis [7]

Answer:

the second and last sentences.

Step-by-step explanation:

Its the most reasonable!

7 0
3 years ago
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Which is the solution set of the inequality 15y-9<36
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