Answer:
perpendicular (90 deg to each other)
Step-by-step explanation:
Incomplete Question the complete Qs is
Which of the following is a correct equation for the line passing through the point (-2,1) and having slope m = 1/2?
a: y=1/2x+2
b: y=-2x+1/2
c: x-2y=-4
d: y-1=1/2(x+2)
Answer:
The Correct option is c. x-2y=-4
Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is

Step-by-step explanation:
Given:

point A(x₁, y₁)=(-2,1)
To Find:
Equation of Line =?
Solution:
Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,
i.e equation in point - slope form
Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2 , 1) we get
As required
Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is

<em><u>Question:</u></em>
Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?
1s
2s
3s
4s
<em><u>Answer:</u></em>
It takes 2 seconds for object to hit the ground
<em><u>Solution:</u></em>
<em><u>The given equation is:</u></em>

Initial velocity = 27 feet/sec

Therefore,

At the point the object hits the ground, h(t) = 0

Solve by quadratic formula,

Ignore, negative value
Thus, it takes 2 seconds for object to hit the ground
Answer:
a = -3
Step-by-step explanation:
3a - 6a + 2 = 8a + 20 - 5a
Combine Like Terms
-3a + 2 = 3a + 20
-2 -2
-------------------------------------
-3a = 3a + 18
-3a -3a
-------------------------------------
-6a = 18
---- ----
-6 -6
a = -3