What is 2/3 of the distance between the points U (-1,4) and B (8,5)

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

7 0

Answer:

Step-by-step explanation:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\U (-1,4)\quad\implies\quad x_1=-1\,,\ \ y_1=4 \\\\B (8,5)\quad\implies\quad x_2=8\,,\ \ y_2=5\\\\\frac12d=\frac23\sqrt{(8+1)^2+(5-4)^2}=\frac23\sqrt{81+1}=\frac23\sqrt{82}\approx6.037$

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Rewrite to suit the format of multiplying two fractions. Remember, dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second. A reciprocal of a fraction is when one switches the place of the numerator and the denominator, that is, the value on top (numerator), and the value on the bottom (denominator).

$\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}$