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3 years ago

CAN SOMEONE HELP ME WITH THIS PROBLEM

Mathematics

2 answers:

Aliun [14]3 years ago

4 0

Sorry I can’t buddy........................................................:(

Sladkaya [172]3 years ago

3 0

Answer:

X = 14

Step-by-step explanation:

First you want to look at the scale ratio to find what the length actually is. So B is 7 times larger then A. So then you want to divide the length of B's side by 7 to find the actual size of As.

28 / 7 = 4

So now that you know the actual length is 4 you can write it into the following equation,

x - 10 = 4

Then you just solve for X

x - 10 = 4

+10 +10

x = 14

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Find all the missing dimensions when a=9, b=13, c=64°

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Answer:

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Part 2) $m\angle A=41.78^o$

Part 3) $m\angle B=74.22^o$

Step-by-step explanation:

step 1

Find the measure of side c

Applying the law of cosines

$c^2=a^2+b^2-2(a)(b)cos(C)$

we have

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substitute

$c^2=9^2+13^2-2(9)(13)cos(64^o)$

$c^2=81+169-234cos(64^o)$

$c^2=250-234cos(64^o)$

$c^2=147.4212$

$c=12.14\ units$

step 2

Find the measure of angle A

Applying the law of sines

$\frac{a}{sin(A)}=\frac{c}{sin(C)}$

substitute the given values

$\frac{9}{sin(A)}=\frac{12.14}{sin(64^o)}$

solve for sin(A)

$sin(A)=\frac{sin(64^o)}{12.14}(9)$

$sin(A)=0.6663$

$m\angle A=sin^{-1}(0.6663)=41.78^o$

step 3

Find the measure of angle B

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$m\angle A+m\angle B+m\angle C=180^o$

substitute the given values

$41.78^o+m\angle B+64^o=180^o$

$m\angle B+105.78^o=180^o$

$m\angle B=180^o-105.78^o$

$m\angle B=74.22^o$

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