Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
V = 1/3 * 3.14 * 11 * 6^2 = 414.48 m^3
cost = V * 20 = 414.48 * 20 = 8289.60
Answer:
No se
Step-by-step explanation:
Answer:
New area: 12ft^2
Step-by-step explanation:
1/3 of 9 is 3
1/3 of 12 is 4
Area = l x w
so 3 x 4 = 12