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2 years ago

Someone help please and make sure the answer is right :)

Mathematics

2 answers:

Alexeev081 [22]2 years ago

4 0

Answer:

- 8°

Step-by-step explanation:

x + 53° = 45° { being alternate angles }

x = 45° - 53°

x = - 8 °

Hope it helps

Yuri [45]2 years ago

3 0

Answer:

x=-8

Step-by-step explanation:

x+53=45

subtract 53 from both sides:

x+53-53=45-53

Simplify:

x=-8

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If costheta=4/5 then what is sec^2theta

DaniilM [7]

Answer:

$\sec^2(\theta)=\frac{25}{16}$

Step-by-step explanation:

Recall what the relationship between cosine and secant:

$\sec(\theta)=\frac{1}{\cos(\theta)}$

In other words, secant is the reciprocal of cosine.

So, if we know cosine, we only need to find its reciprocal to find secant.

We are given that cosine is:

$\cos(\theta)=\frac{4}{5}$

Then secant must be:

$\sec(\theta)=\frac{5}{4}$

So:

$\sec^2(\theta)=(\frac{5}{4})^2$

Square:

$\sec^2(\theta)=\frac{25}{16}$

And we're done!

5 0

3 years ago

The time that a butterfly lives after emerging from its chrysalis can be modelled by a random variable T, the model here taking

olasank [31]

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8 0

3 years ago

1011+111 in binary form

Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0

3 years ago

Simplify.

aleksklad [387]

618 hope this helps you have an amazing week

4 0

2 years ago

What is the range of the function on the graph?

Ainat [17]

Check the picture below.

includes 2, notice, it doesn't go below 2 over the y-axis, and then it keeps on going up. So, the range is from +2 onwards.

4 0

3 years ago

Read 2 more answers