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Vladimir [108]
2 years ago
10

Someone help please and make sure the answer is right :)

Mathematics
2 answers:
Alexeev081 [22]2 years ago
4 0

Answer:

- 8°

Step-by-step explanation:

x + 53° = 45° { being alternate angles }

x = 45° - 53°

x = - 8 °

Hope it helps

Yuri [45]2 years ago
3 0

Answer:

x=-8

Step-by-step explanation:

x+53=45

subtract 53 from both sides:

x+53-53=45-53

Simplify:

x=-8

You might be interested in
If costheta=4/5 then what is sec^2theta
DaniilM [7]

Answer:

\sec^2(\theta)=\frac{25}{16}

Step-by-step explanation:

Recall what the relationship between cosine and secant:

\sec(\theta)=\frac{1}{\cos(\theta)}

In other words, secant is the reciprocal of cosine.

So, if we know cosine, we only need to find its reciprocal to find secant.

We are given that cosine is:

\cos(\theta)=\frac{4}{5}

Then secant must be:

\sec(\theta)=\frac{5}{4}

So:

\sec^2(\theta)=(\frac{5}{4})^2

Square:

\sec^2(\theta)=\frac{25}{16}

And we're done!

5 0
3 years ago
The time that a butterfly lives after emerging from its chrysalis can be modelled by a random variable T, the model here taking
olasank [31]
Xd answer is d I hope u find the answer
8 0
3 years ago
1011+111 in binary form
Ann [662]

Answer:

10010

Step-by-step explanation:

1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0

111=1(2)^2+1(2)^1+1(2)^0

So 1011+111 gives us:

1(2)^3+0(2)^2+1(2)^1+1(2)^0

+

1(2)^2+1(2)^1+1(2)^0

-----------------------------------------------------

Combine like terms:

1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0

1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace 2^0 with 1 and 2 with (2)^1:

1(2)^3+1(2)^2+(2)^2+(2)^1(1)

I want a 2^0 number:

1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0

Combine like terms:

1(2)^3+2(2)^2+1(2)^1+0(2)^0

2(2)^2=2^3:

1(2)^3+2^3+1(2)^1+0(2)^0

Combine like terms:

2(2)^3+1(2)^1+0(2)^0

We can rewrite the first term by law of exponents:

2^4+1(2)^1+0(2)^0

1(2)^4+1(2)^1+0(2)^0

So the binary form is:

10010

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

      1     0     1      1

+            1      1      1

------------------------------

     (1)    (1)    (1)

      1     0     1      1

+            1      1      1

------------------------------

     1 0    0     1       0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0
3 years ago
Simplify.
aleksklad [387]

618 hope this helps you have an amazing week

4 0
2 years ago
What is the range of the function on the graph?
Ainat [17]
Check the picture below.

includes 2, notice, it doesn't go below 2 over the y-axis, and then it keeps on going up.  So, the range is from +2 onwards.

4 0
3 years ago
Read 2 more answers
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