The inequality is still true! If you add a number, say 5 to both sides of the following inequality, does anything change?
3 < 6
3 + 5 < 6 + 5
8 < 11
The inequality is still true. We know the statement holds for subtracting the same number because, in a way, addition and subtraction are pretty much the same operation. If I subtract 5 from both sides, I can think of it like "I add negative 5 to both sides" or something along those lines. It's kind of backwards thinking.
Answer:
3x -7y = 0
Step-by-step explanation:
Parallel lines have the same slope.
Changing the constant in a linear equation like this only changes the y-intercept. It has no effect on the slope of the line. So, we can change the constant from 4 to 0 and we will have a line with the same slope, parallel to the original, but with a different y-intercept.
The "standard form" of the equation of a line has the leading coefficient positive. We can make that be the case by using the multiplication property of equality, multiplying both sides of the equation by -1.
Parallel line:
-3x +7y = 0
In standard form:
3x -7y = 0
Answer:

Step-by-step explanation:
The Given question is INCOMPLETE as the statements are not provided.
Now, let us try and solve the given expression here:
The given expression is: 
Now, the BINOMIAL EXPANSION is the expansion which describes the algebraic expansion of powers of a binomial.
Here, 
or, on simplification, the terms of the expansion are:

The above statement holds for each n > 0
Hence, the complete expansion for the given expression is given as above.
One of them will be given 4 biscuits and the other will be given 24.
old weight - decrease = new weight
decrease = weight * percent
decrease = 72 * .125 = 9 lbs
old weight - decrease = new weight
72 - 9 = new weight
63 lbs
A healthy weight for the dog is 63 lbs