Th matrix is missing. The matrix is :
Solution :
The column of the matrix are 
, 
, 
Now each of them are vectors in 
. But has dimensions of 2. But there are 3 column vectors, hence they are linearly dependent.
Therefore, the column of the given matrix does not form the 
as the set contains 
than there are entries in each vector.
Therefore, option (D) is correct.
Answer:
Look below
Step-by-step explanation:
A vertical line doesn't intercept the y-axis, therefore the equation would be x=b in which b is where the line intercepts the x-axis.
For Y=2x+10 X=y/2 -5. Second x/3
1) The domain is all the possible x values in the function so it would be [-4,4]
2) There are only 3 zeros shown on the graph and they are (-2, 0) (0, 0) (2, 0) the zeros are the value of x when y = 0.
3)The function is positive/Negative is asking for what x values make the y values positive aka interval notation. The function is positive if x = (0, 2) because 0 and 2 aren't included you use parentheses () instead of brackets []
The function is negative if x [-4, -2), (-2,0), (2,4]
