Simply and solve this equation for q: 3q +5 +2 q -5 =65

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

3 0

Hello,

3q+5+2q-5=65
==>5q=65
==>q=13

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Answer:

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Find the area of the region that lies inside the first curve and outside the second curve. r = 6 − 6 sin θ, r = 6

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Each curve completes one loop over the interval $0\le t\le2\pi$ . Find the intersections of the curves within this interval.

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The region of interest has an area given by the double integral

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equivalent to the single integral

$\displaystyle\frac12\int_\pi^{2\pi}\bigg((6-6\sin\theta)^2-6^2\bigg)\,\mathrm d\theta$

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