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2 years ago

13

There were 16 dogs in line for the dog show parade. Popsie the poodle is the 12th dog in line. How many dogs are ahead of her? H

ow many dogs are behind her? Draw a picture to help you find the answers.

2 answers:

Artemon [7]2 years ago

4 0

There is 4 in front and 11 behind. I hope this helps!

Ann [662]2 years ago

3 0

11 are ahead, 4 are behind

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yawa3891 [41]

You have that the scale factor is 8 and the length of the figure is 10 yards. Therefore, to solve this exercise, and calculate the length of the image, you must follow the proccedure below:

1. If the scale factor is 8, this means that lenght of the image is 8 times bigger.

2. Keeping this on mind, you only have to multiply 8 by 10 yards, as below:

Length of the image=8x10 yards
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3. Therefore, the answer is the option C:

C. 80 yd

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3 years ago

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VikaD [51]

<u>4 less than n is -15</u>

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4<15

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2 years ago

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2 years ago

sin alpha = 7/25, alpha lies in quadrant ii, and cos beta = 2/5, beta lies in quadrant i. find cos(alpha-beta).

Ilia_Sergeevich [38]

Answer:

Therefore $\cos(\alpha-\beta)=\frac{48+7\sqrt{25}}{125}$

Step-by-step explanation:

Given values are

$\sin \alpha=\frac{7}{25}$

$\cos \beta=\frac{2}{5}$

$\sin^2x+\cos^2=1$

$\cos \alpha=\sqrt{1-\sin^2\alpha}$

$\cos \alpha=\sqrt{1-(\frac{7}{25})^2}$

$\cos \alpha=\sqrt{1-\frac{49}{625}}$

$\cos \alpha=\sqrt{\frac{576}{625}}$

$\cos \alpha=\frac{24}{25}$

$\sin \beta=\sqrt{1-\cos^2\beta}$

$\sin \beta=\sqrt{1-(\frac{2}{5})^2}$

$\sin \beta=\sqrt{1-\frac{4}{25}}$

$\sin \beta=\frac{\sqrt{21}}{5}$

$\cos(\alpha-\beta)=\cos\alpha\cos\beta+\sin\alpha\sin\beta$

$\cos(\alpha-\beta)=\frac{24}{25}\times\frac{2}{5}+\frac{7}{25}\times\frac{\sqrt{21}}{5}$

$\cos(\alpha-\beta)=\frac{48+7\sqrt{25}}{125}$

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2 years ago

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Gnesinka [82]

IQR is the Q3 - Q1

Put the data in order.....

6, 7, 11, 13, 14, 15, 15, 19, 21
^ ^ ^
9(Q1) 14(Q2) 17(Q3)

17 (Q3) - 9 (Q1) = 8 (IQR)

So the answer to your question is the first option, 8.

Hope this helps! :D

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3 years ago