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3 years ago

X-14<-6x+7≤13 solve for x

Mathematics

1 answer:

m_a_m_a [10]3 years ago

8 0

Answer:

−1 ≤ x < 3

Step-by-step explanation:

Solve the system of inequalities.

X must be equal to or greater then -1 and smaller then 3.

You options are -1, 0, 1, & 2

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Helpppppp please thank you

AleksandrR [38]

Answer:

5/21

Step-by-step explanation:

5/3 divide by 7

5/3 / 7/1

5/3 x 1/7

5/21

i think its this

4 0

3 years ago

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Find the area of the rectangle as a single expression.

qwelly [4]

Answer:

D) $15x^2 +6x-48$

Step-by-step explanation:

$Area \: of \: rectangle \\ = length \times width \\ = 3(x + 2) \times (5x - 8) \\ = (3x + 6) \times (5x - 8) \\ = 3x(5x - 8) + 6(5x - 8) \\ = 15 {x}^{2} - 24x + 30x - 48 \\ = 15 {x}^{2} + 6x - 48$

7 0

3 years ago

Mrs. Ishimitsu is installing a rubber bumper around the edge of her coffee table. The dimensions of the rectangular table are (2

ollegr [7]

Answer:

$2x^2+8x-30$ represents the total perimeter of the table, and if x = 3 the lentgh of entire rubber bumper is 12 feet.

Step-by-step explanation:

Perimeter is defined as the sum of sides.

For a rectangle having dimension length 'L' and breadth 'B' Since, rectangle has two sides equal.

Perimeter of rectangle = 2 ( length + breadth )

Here, given rectangle has dimension

Length = $2x^2-16$ and breadth = $-x^2+4x+1$

Thus, perimeter of rectangle = $2(2x^2-16+(-x^2+4x+1))$

$=2(2x^2-16-x^2+4x+1)$

$=2(x^2+4x-15)$

$=2x^2+8x-30$

Thus, perimeter of rectangle is $2x^2+8x-30$ ........(1)

Perimeter of rectangle , when x = 3,

Put x= 3 in (1) ,

$2x^2+8x-30\Rightarrow 2(3)^2+8(3)-30 \Rightarrow 18+24-30=12$

Thus, $2x^2+8x-30$ represents the total perimeter of the table, and if x = 3 the lentgh of entire rubber bumper is 12 feet.

5 0

3 years ago

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Find the with of a triangle as a 15 cm high in a hypogynous of a 19 cm

Inessa05 [86]

Answer:

This other side of the triangle is equal to about 11.7 cm

Step-by-step explanation:

In order to find out the third side of the triangle we will just use the Pythagoras Theorem.

$c^{2} =a^{2} + b^{2}$

Since we know the hypotenuse and we know one of the legs, in order to find the second leg we just substitute the values and solve the equation and so we get...

$c^{2} =a^{2} + b^{2}\\19^{2} = 15^{2} + b^{2}\\361 = 225 + b^{2} \\$

$b^{2} = 361 - 225\\b^{2} = 136\\b = \sqrt{136} \\$

And so b ≈ 11.66190

8 0

3 years ago

Calculate (a) the total installment price, (b) the carrying charges, and (c) the number of months needed to save the money at th

Genrish500 [490]

A) The total installment price is ($28/mo)*(24 mo) = $672.00

b) The carrying charges are $672.00 -500.00 = $172.00

c) The number of months of saving required is 500/28 ≈ 18.

3 0

3 years ago

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