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Alisiya [41]
3 years ago
10

Geometry !!! True or false question

Mathematics
1 answer:
lara [203]3 years ago
7 0
Rectangle
QT = RS 
QR = TS  

but QR = 25 and TS = 29.15
so it's false....

answer
FALSE
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Geraldine is picking a four-digit password by using the digits 0 through 9. She can use each digit only once. How many different
Archy [21]

0-9 = 10 numbers

 1st digit can be 1 0f 10

2nd digit can be 1 of 9

3rd digit can be 1 of 8

4th digit can be 1 of 7



10 * 9 *8*7 = 5040 different combinations

6 0
3 years ago
Read 2 more answers
Stephen kicked a ball inside. The equation that represents the height h in feet of the ball after being kicked and elapsed amoun
kodGreya [7K]

Answer:

The maximum height of the ball is: 14.0625ft

Step-by-step explanation:

The missing information is:

h(t) = 30t - 16t^2

Required

The maximum height the ball attained

First, we calculate the time to reach the maximum height.

For a function: h(t) = at^2 + bt + c

The maximum is: t = \frac{-b}{2a}

So, the maximum of h(t) = 30t - 16t^2 is:

t = \frac{-b}{2a}

Where

a = -16; b = 30

So:

t = -\frac{30}{2*-16}

t = -\frac{30}{-32}

t = \frac{30}{32}

t = 0.9375

The maximum height is then calculated as:

h(t) = 30t - 16t^2

h(0.9375) = 30 * 0.9375- 16 * 0.9375^2

h(0.9375) = 28.125- 14.0625

h(0.9375) = 14.0625

8 0
3 years ago
What is 1/8% of 1000
Luden [163]

Answer:

12500

Step-by-step explanation:

1/8%x1000=12500

8 0
3 years ago
Read 2 more answers
Simplify -6i(8-6i)(-8-8i)
padilas [110]

Answer:

-96 + 672\,i

Step-by-step explanation:

This is a product of complex numbers, so we have in mind not only the general rules for multiplying binomials, but also the properties associated with the powers of the imaginary unit "i", in particular i^2=-1

We start by making the first product indicated which is that of a pure imaginary number (-6i) times the complex number (8-6i). We use distributive property and obtain the new complex number that results from this product:

-6\,i\,(8-6\,i)= (-6\,i)\,* 8 \, -\,6\,i\,(-6\,i)=-48\,i+36\,i^2=-48\,i+36\,(-1)=-36-48\,i

Now we make the second multiplication indicated (using distributive property as one does with the product of binomials), and combine like terms at the end:

(-36-48\,i)\,(-8-8\.i)=(-36)\.(-8)+(-36)(-8\,i)+(-48\,i)\,(-8)+(-48\,i)(-8\,i)=\\=288+288\,i+384\,i+384\,i^2=288+288\,i+384\,i+384\,(-1)=\\=288-384+288\,i+384\,i=-96+672\,i

5 0
3 years ago
Integrate the following
enot [183]

I suppose you mean to have the entire numerator under the square root?

\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx

We can use a trigonometric substitution to start:

x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt

Then for x=2, t=\sec^{-1}1=0; for x=4, t=\sec^{-1}2=\frac\pi3. So the integral is equivalent to

\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt

We can write

\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t

so the integral becomes

\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}

7 0
3 years ago
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