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Ronch [10]
3 years ago
11

There are 18 football teams in a league,

Mathematics
1 answer:
12345 [234]3 years ago
4 0

Answer:

306

Step-by-step explanation:

18x17=306

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Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
Translate the sentence into an equation.
Dmitriy789 [7]

Answer:

I think it could be 8+6+y

Step-by-step explanation: I dont really know but dont delete this. Can I be Brainlyest please?

5 0
2 years ago
Three friends were born in consecutive years. The some of their birth years is 5982.find the year in which each person was born
posledela
A+b+c=5982
find the average of the three friends 
5982/3=1994
add and subtract one to find the average 
1994+1=1995
1994-1=1993
add all the years together to check 
1993+1994+1995=5983
3 0
3 years ago
What transformation is used to transform b into figure C?
givi [52]
On order to change B to C, you have to bring B 3 units to the right and then 4 units down.
8 0
3 years ago
Can someone please help me out ASAP
belka [17]
The answer is x=2 i hope this helps !!
5 0
3 years ago
Read 2 more answers
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