There are 18 football teams in a league,

Leo purchases a 4 1/2 pound bag of chicken. He uses 2 1/3 pounds of chicken for a chicken taco. How many pounds of chicken does

Maurinko [17]

Answer:

2 1/6 lbs. of chicken left

Step-by-step explanation:

4 1/2 - 2 1/3

9/2 - 7/3

27/6 - 14/6

13/6 = 2 1/6

3 0

3 years ago

15.Identify the coordinates of point C after a translation with rule (x + 3, y 2).

ziro4ka [17]

Since the original coordinates are (-3,4), you can start finding the prime coordinates by adding 3 to the x-value, and subtracting 2 from the y-value. This will get you (-3+3, 4-2) This will come out to (-0, 2), so your answer will be...

D. C'= (0,2)

6 0

3 years ago

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I have 10 mins to turn this in... please help

marin [14]

Found this on socratic !!! hope this helps !!!!

5 0

2 years ago

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HELP PLEASE !!!

enot [183]

Given: m ∠3 = m ∠4

To Prove: ∠1, ∠2 are supplementary .

Proof : m ∠3 = m ∠4 ( Given) ------------(1)

m<2 + m< 3 = 180 degrees ( <2 and <3 form a linear pair). ----------(2)

m< 4 = m<1 (Vertical angles are equal) -----------(3).

Substituting, m<4 =m<1 in (1), we get

m ∠3 = m ∠1.

Now, substituting m ∠3 = m ∠1 in (2), we get

m<2 + m< 1 = 180 degrees.

Sum of m <1 and m<2 is 180 degrees.

Therefore,<em> ∠1, ∠2 are supplementary by the defination of supplementary angles.</em>

3 0

2 years ago

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4. Assume that the chances of a basketball player hitting a 3-pointer shot is 0.4 and the probability of hitting a free-throw is

vovikov84 [41]

Answer:

0.0334 = 3.34% probability that the player will make exactly 3 3-pointers and 5-free throws.

Step-by-step explanation:

For each 3-pointer shot, there are only two possible outcomes. Either the player makes it, or the player does not. The same is valid for free throws. This means that both the number of 3-pointers and free throws made are given by binomial distributions.

Since 3-pointers and free throws are independent, first we find the probability of making exactly 3 3-pointers out of 10, then the probability of making exactly 5 free throws out of 10, and then the probability that the player will make exactly 3 3-pointers and 5-free throws is the multiplication of these probabilities.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of making 3 3-pointers out of 10:

The chances of a basketball player hitting a 3-pointer shot is 0.4, which means that $p = 0.4$ . So this is $P(X = 3)$ when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.21499$

Probability of making 5 free throws out of 10:

The probability of hitting a free-throw is 0.65, which means that $p = 0.65$ . The probability is $P(X = 5)$ when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{10,5}.(0.65)^{5}.(0.35)^{5} = 0.15357$

Calculate the probability that the player will make exactly 3 3-pointers and 5-free throws.

0.21499*0.15537 = 0.0334

0.0334 = 3.34% probability that the player will make exactly 3 3-pointers and 5-free throws.

5 0

2 years ago