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Leokris [45]
3 years ago
5

A principal randomly chose 40 students from grade 7. Of these students, 9 were wearing watches. Based on this information, what

is the most reasonable prediction of the number of students wearing watches in a group of 480 students from grade 7?
F 180
G 12
H 360
J 108
Mathematics
1 answer:
Snezhnost [94]3 years ago
5 0

Answer:

108

Step-by-step explanation:

480 is 12 times more then 40 therefore 108 is 12 times 9 so it's the answer

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Between two integers does 42lie on the number line? I really need this answered!!
topjm [15]

Answer:

b. between 6 and 7

Step-by-step explanation:

As

36<42<49

√36<√42<√49

6<√42<7

So it is between 6 and 7

8 0
3 years ago
Read 2 more answers
The table shows the hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale. Grade 7 Grade 8 20 21 15
Naddika [18.5K]

Answer:

1. The interquartile range for the grade 7 data is 6.

2. The interquartile range for the grade 8 data is 6.

3. The difference of the medians of the two data sets is 2.

4. The difference is about 1/3 times the interquartile range of either data set.

Step-by-step explanation:

The hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale is given by the following table.

Grade 7       Grade 8

  20                  21

  15                  29

  30                  14

  24                  19

   18           24

   21                 25

The data set for grade 7 is

20, 15, 30, 24, 18, 21

Arrange the data in ascending order.

15, 18, 20, 21, 24, 30

Divide the data in four equal parts.

(15), 18, (20), (21), 24,( 30)

Q_1=18, Median=\frac{20+21}{2}=20.5, Q_3=24

The interquartile range for the grade 7 data is

IQR=Q_3-Q_1=24-18=6

Therefore the interquartile range for the grade 7 data is 6.

The data set for grade 8 is

21, 29, 14, 19, 24, 25

Arrange the data in ascending order.

14, 19, 21, 24, 25, 29

Divide the data in four equal parts.

(14), 19, (21), (24), 25, (29)

Q_1=19, Median=\frac{21+24}{2}=22.5, Q_3=25

The interquartile range for the grade 8 data is

IQR=Q_3-Q_1=25-19=6

Therefore the interquartile range for the grade 8 data is 6.

The difference of the medians of the two data sets is

D=22.5-20.5=2

Therefore the difference of the medians of the two data sets is 2.

Let the difference is about x times the interquartile range of either data set.

The IQR of each data is 6.

D=x(IQR)

2=x(6)

\frac{2}{6}=x

\frac{1}{3}=x

Therefore the difference is about 1/3 times the interquartile range of either data set.

8 0
3 years ago
Help please, i dont understand
yan [13]

Answer:

formula: y-y1 = m(x-x1)

Step-by-step explanation:

General:

1. find 2 points directly on the line and apply the formula y2-y1 over x2-x1 this answer equals m

2. then add it into the formula y-y1 = m(x-x1) remember x and y are variables so only put numbers in y1 and x1

3. solve the problem

Example:

line 1:

1. y2-y1 over x2-x1 is 4-6 over 6-4 = -1

2.  y-6 = -1(x-(-4) or y-6 = -1(x+4)

3. y-6 = -1x-4

4. y = -1x-2

3. the gradient equals: y = -1x-2

Hope this helps :) Let me know if you need a better example

5 0
3 years ago
A hole the size of a photograph is cut from a red piece of paper to use in a picture frame. What is the area of the piece of red
loris [4]

Answer:

D 47 square units.

5 0
3 years ago
Read 2 more answers
What is wrong with this histogram?
Marta_Voda [28]
The intervals along the x axis are inconsistent. the one that says 21-30 should either be split into 2 or have twice the width.

Hope this helps :)
3 0
3 years ago
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