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gavmur [86]
2 years ago
7

What is wrong with this histogram?

Mathematics
1 answer:
Marta_Voda [28]2 years ago
3 0
The intervals along the x axis are inconsistent. the one that says 21-30 should either be split into 2 or have twice the width.

Hope this helps :)
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Look at the picture
ValentinkaMS [17]

Answer: 54

Step-by-step explanation:

3 times the square of -3 plus -5 times -3 plus 12

3 times 9 + 15 + 12

27+15+12=

54

7 0
3 years ago
1
gayaneshka [121]

Step-by-step explanation:

OOOO

BYE

8 0
3 years ago
Can I have help with the problem in the picture pls​
Bumek [7]
A is the correct answer !
8 0
2 years ago
The volume of the cylinder above is 2,314.25, and the radius of the base is 8.9 Find the volume of the cone.
olga55 [171]

Answer: 771.41\ units^3

Step-by-step explanation:

The missing figure is attached.

The volume of an oblique cylinders and the volume of  a right cylinder can be found with this formula:

V_{cy}=\pi r^2h

Where "r" is the radius and "h" is the height.

The volume of an oblique cone and the volume of  a right cone can be found with this formula:

V_{co}=\frac{1}{3}\pi r^2h

Where "r" is the radius and "h" is the height.

According to the information given in the exercise, you know that the volume of the cylinder and also the radius of the cylinder and the cone ,are the following:

V_{cy}=2,314.25\ units^3\\\\r=8.9\ units

Therefore, in order to find the volume of the cone, you only need to multiply the volume of the cylinder by \frac{1}{3}.

Then, you get:

V_{co}=\frac{1}{3}(2,314.25\ units^3)\\\\V_{co}=771.41\ units^3

8 0
2 years ago
Read 2 more answers
Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 42-m-42-m squar
oee [108]

The area enclosed by the figure is 4533.48 square meters.

<u>Step-by-step explanation:</u>

Side length of the square = 42m

The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.

Radius of the semicircle = 21m

Area of the square = 42 x 42 = 1764 square meters

Area of 1 semicircle = π(21 x 21) /2

= (3.14) (441) /2

= 1384.74/2

= 692.37 square meters

Area of 4 semicircle = 4 x 692.37

= 2769.48 square meters

Total area = 1764 + 2769.48

= 4533.48 square meters

The area enclosed by the figure is 4533.48 square meters.

7 0
3 years ago
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