3(6-2) = (?*6) - (3*2)
? would be equal to 3
Answer:
1. Nominal
2. Interval
3. Interval
4. Nominal.
Step-by-step explanation:
Nominal scales are used when the variable we're interested in has NO quantitative value.
Therefore, the college you are enrolled in and your hometown are examples of nominal data.
Interval scales are used when the variable we are interested in has quantitative value and the values have an order and the difference between each value is the same.
For the case of number of students, we know, for example, that 20 students < 21 students, and the difference between 20 and 21 is the same as the one between 21 and 22. The same applies for the age of your classmates.
Therefore, the age of your classmates and the number of students in a statistics course is an interval data.
The answer is d because if you sketch it out it'll show d to have the vertical angle
YOUR A BTS ARMY TOO? SAMEEEE OMGGG
First, an introduction: If the equation of the circle were x^2 + y^2 = 144, then the center would be at (0,0) and the radius would be 12. Note that the distance from the center to P(10,10) is 10sqrt(2), or 14.14. Thus, in this example, P would be OUTSIDE the circle (since 14.14 is greater than the radius 12).
Now let's focus on <span>(x-1)^2 + (y-2)^2 =144. Let x = 12 as an example; find the corresponding y: 9^2 + (y-2)^2 = 144, or (y-2)^2 = 63, and so y-2 is approx. -8 or +8. Then y (for x = 12) is either approx. -10 or 6: (12,-10) or (12,6). Are these inside the circle or outside?
A better way to address this would be as follows:
Find the distance from the center (1, 2) to the point P(10,10). If this distance is less than 12, the point P is inside C; if greater than 12, P is outside C.
This distance is sqrt( (10-2)^2 + (10-1)^2 ), or sqrt (64+81) = sqrt(145).
This is LARGER than sqrt(144). Thus, P is OUTSIDE the circle C.</span>
