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2 years ago

#13 w is the solution of the equation. 3 = b + 3

2 answers:

7 0

I'm assuming that you meant what is the solution of the equation.

b would equal 0.

This is because it is a simple one step equation; subtract 3 from both sides which leaves you with 0 = 3.

Hope this helps!

Ulleksa [173]2 years ago

3 0

3-3=b+3-3
solve each side
0=b

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Find an exponential function that passes through each pair of points.<br><br>(2,1.75) & (-2,28)

dusya [7]

Answer:

$f(x) = 7\, ((1/2)^{x})$ .

Step-by-step explanation:

An exponential function is typically in the form $f(x) = a\, (b^{x})$ , where $a$ and $b$ ( $b > 0$ ) are constants to be found.

In this question:

$f(2) = 1.75$ means that $a\, (b^{2}) = 1.75$ .

$f(-2) = 28$ means that $a\, (b^{-2}) = 28$ .

Divide one of the two equations by the other to eliminate $a$ and solve for $b$ .

The number of the right-hand side of the second equation is larger than that of the first equation. Hence, divide the second equation with the first:

$\displaystyle \frac{a\, (b^{-2})}{a\, (b^{2})} = \frac{28}{1.75}$ .

$\displaystyle b^{-4} = 16$ .

$b^{-1} = 2$ .

$\displaystyle b = \frac{1}{2}$ .

Substitute $b = (1/2)$ back into either equation (for example, the first equation) and solve for $a$ :

$a\, ((1/2)^{2}) = 1.75$ .

$a = 7$ .

Substitute $a = 7$ and $b = (1/2)$ into the other equation. That equation should also be satisfied.

Therefore, this function would be:

$f = 7\, ((1 / 2)^{x})$ .

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2 years ago

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2 years ago

Read 2 more answers

If the mean of five values is 8.6 and four of the values are 10, 7, 8, and 7, find

Anna007 [38]

Answer:

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2 years ago

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Stolb23 [73]

4cm = 5km

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Hope this helps! :)

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3 years ago

A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set w

VashaNatasha [74]

Complete Question

A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:

a)F minimum

b) F maximum

c) Frequency resolution

Answer:

a) $Fmax=100Hz$