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SpyIntel [72]
3 years ago
11

Katenka cross country skied a trail that was 3/4 mile each way. after skiing 2/3 of the trail she turned around. What fraction o

f a mile did katenka ski before she turned around.
Mathematics
1 answer:
allsm [11]3 years ago
3 0
We know that

[total trail]=(3/4)*2------> 6/4---------> (3/2) miles

<span>[fraction of a mile that katenka did]=(2/3)*(3/2)------> 1 mile

the answer is 1 mile</span>
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Recall from Intermediate Algebra that two non-vertical lines are perpendicular if and only if they have negative reciprocal slop
OLEGan [10]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The line is y  =  -4 x

Step-by-step explanation:

From the question we are told that

The line is y  =  \frac{1}{4} x  + 8

The point is P(0,0 )

Generally the equation for a line is yn =  mx  + c

Now comparing this with the given equation we see that

m  =\frac{1}{4} =  slope

C  =8  =  intercept

Generally the slope of the perpendicular to the given line is mathematically evaluated as

m_1  = -  \frac{1}{m}

=> m_1  = -  \frac{1}{ \frac{1}{4}}

=> m_1  = -4

Generally from the univesal equation of a line and the given point we have that

y = mx + c at p(0,0) and m_1 =  -4 is

0 = -4 (0 ) + c

=> c = 0

Hence the equation perpendicular to the line given at the point given is

y  =  -4 x

8 0
3 years ago
Solve the following equation for aa. Be sure to take into account whether a letter is capitalized or not.
Snezhnost [94]

Answer:

Since you state that capitalization is important, then we can see that it is not possible to solve the equation for F.

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Step-by-step explanation:

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3 years ago
The time needed to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes
Komok [63]

Answer:

a. The probability of completing the exam in one hour or less is 0.0783

b. The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. The number of students will be unable to complete the exam in the allotted time is 8

Step-by-step explanation:

a. According to the given we have the following:

The time for completing the final exam in a particular college is distributed normally with mean (μ) is 77 minutes and standard deviation (σ) is 12 minutes

Hence, For X = 60, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=60−77 /12

Z=−1.4167

Using the standard normal table, the probability P(Z≤−1.4167) is approximately 0.0783.

P(Z≤−1.4167)=0.0783

Therefore, The probability of completing the exam in one hour or less is 0.0783.

b. In this case For X = 75, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=75−77 /12

Z=−0.1667

Using the standard normal table, the probability P(Z≤−0.1667) is approximately 0.4338.

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is obtained as follows:

P(60<X<75)=P(Z≤−0.1667)−P(Z≤−1.4167)

=0.4338−0.0783

=0.3555

​

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. In order to compute  how many students you expect will be unable to complete the exam in the allotted time we have to first compute the Z−score of the critical value (X=90) as follows:

Z=  X−μ /σ

Z=90−77 /12

Z​=1.0833

UsING the standard normal table, the probability P(Z≤1.0833) is approximately 0.8599.

Therefore P(Z>1.0833)=1−P(Z≤1.0833)

=1−0.8599

=0.1401

​

Therefore, The number of students will be unable to complete the exam in the allotted time is= 60×0.1401=8.406

The number of students will be unable to complete the exam in the allotted time is 8

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