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kolbaska11 [484]
3 years ago
8

What is the area of the label on a can of corn with a radius of 3 inches and a height of 6 inches? Use 3.14 as pi and round to t

he nearest hundreth.
Possible answers;
169.56 square inches

113.04 square inches

339.12 square inches

56.52 square inches
Mathematics
2 answers:
ad-work [718]3 years ago
7 0

Answer:

169.56

Step-by-step explanation:

A=2πrh+2πr2

sattari [20]3 years ago
4 0
113.04 so thats the answer
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strojnjashka [21]
The answer is 24 + 0.057

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3 years ago
Which is equivalent to (3 + 2i)(5 + i)?
zepelin [54]
(3 + 2i)(5 + i)
15 + 3i + 10i + 2i^2
15 + 13i - 2
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5 0
2 years ago
Point F is at (0, -10) and point H is at (-6, 5). Find the coordinates of point G on line segment FH such that the ratio of FG t
Tanya [424]

Answer:

G(x,y)=(-4,0)

Step-by-step explanation:

We use the section formula:

(x,y)=\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right)

Given:

F(x_1,y_1)=(0, -10)\\H(x_2,y_2)=(-6, 5)\\FG:GH=m:n=2:1

We substitute the values to get:

G(x,y)=\left(\dfrac{2*-6+1*0}{2+1}, \dfrac{2*5+1*-10}{2+1}\right)\\=\left(\dfrac{-12}{3}, \dfrac{10-10}{3}\right)\\=\left(\dfrac{-12}{3}, \dfrac{0}{3}\right)\\\\G(x,y)=(-4,0)

5 0
3 years ago
Help with number 3 please
frozen [14]

Answer:

A biconditional statement is a combination of a conditional statement Its converse written in the if and only form

8 0
2 years ago
manufacturing company produces digital cameras and claim that their products maybe 3% defective. A video company, when purchasin
alexdok [17]

Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) nCr q^{r} p^{n-r}

nCr = \frac{n!}{(n-r)!r!}

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = 20C18 * 0.97^{18} * 0.03^{20-18}

P(X=18) = 20C18 * 0.97^{18} * 0.03^{2}

P(X=18) = 0.0988

P(X=19) = 20C19 * 0.97^{19} * 0.03^{20-19}

P(X=19) = 20C19 * 0.97^{19} * 0.03^{1}

P(X=19) = 0.3364

P(X=20) = 20C20 * 0.97^{20} * 0.03^{20-20}

P(X=20) = 20C20 * 0.97^{20} * 0.03^{0}

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

6 0
3 years ago
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