Answer:
The area of the shaded region is ![8\pi\ units^2](https://tex.z-dn.net/?f=8%5Cpi%5C%20units%5E2)
Step-by-step explanation:
we know that
The area of complete circle subtends a central angle of 2π radians
so
A central angle of π radians subtends an area of semicircle
The area of semicircle is given by the formula
![A=\frac{1}{2}\pi r^{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5Cpi%20%20r%5E%7B2%7D)
we have
![r=4\ units](https://tex.z-dn.net/?f=r%3D4%5C%20units)
substitute
![A=\frac{1}{2}\pi (4)^{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5Cpi%20%20%284%29%5E%7B2%7D)
![A=8\pi\ units^2](https://tex.z-dn.net/?f=A%3D8%5Cpi%5C%20units%5E2)
therefore
The area of the shaded region is ![8\pi\ units^2](https://tex.z-dn.net/?f=8%5Cpi%5C%20units%5E2)
To help solve this problem, create an equation.
Let x = number of notebooks
$30 = $22.50 + $1.50x. Subtract $22.50 from each side.
$7.5 = $1.50x. Divide each side by $1.50.
5 = x.
Morgan bought 5 notebooks.
Answer:
1/8 inches
A type of cracker, rectangular in shape, is stored in a vertical column with all of the crackers stacked directly on top of each other. Each cracker measures 2 inches in length by inches in width. The volume of the column is 15 inches cubed. If there are 40 crackers in the column, what is the height of each individual cracker?
*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆
Answer: Lets say that each tower can be build with 1 block, then you can build 257 towers
Explanation:
I hope this helped!
<!> Brainliest is appreciated! <!>
- Zack Slocum
*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆
Answer:
B, c
Step-by-step explanation: