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olga nikolaevna [1]
3 years ago
15

An 80 meter rope is suspended at its two ends from the tops of two 50 meter flagpoles. If the lowest point to which the midpoint

of the rope can be pulled is 36 meters from the ground, then the distance, in meters, between the flagpoles is:
A. 6√39
B. 36√13
C. 12√39
D. 18√13
E. 12√26
Please ignore the other doodles in the picture

Mathematics
2 answers:
Agata [3.3K]3 years ago
7 0

Answer:

qwerty

Step-by-step explanation:

Rudiy273 years ago
6 0
36 m above the ground is 14 m below the top of the pole.
distance between poles = 2√[40²-14²]
= 12√39
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lyudmila [28]
The two data sets overlap three times total, at 35 and 40. I would say there is moderate overlap
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4 years ago
What is the y intercept of the function f(x)=2•3^x
kykrilka [37]

Answer:

\boxed{Option \ A}

Step-by-step explanation:

f(x) = 2*3^x

y intercept is when x = 0

So, Putting x = 0 in the above function

=> f(0) = 2*3^0

=> f(0) = 2*1

=> f(0) = 2

So, y-intercept is (0,2)

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3 years ago
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7 0
3 years ago
The surface area of a given cone is 1,885.7143 square inches. What is the slang height?
nasty-shy [4]

This question is not complete. This is because it lacks the appropriate diagram containing necessary information to solve this question.

Please find attached the appropriate diagram to solve for this question

Complete Question :

The surface area of a given cone is 1,885.7143 square inches. What is the slant height?

Answer:

25 inches

Step-by-step explanation:

In the diagram, we are given the following information

Height of the cone = 20 inches

Radius of the cone = 15 inches.

The formula for the slant height of a cone represented by l =

l² = r² + h²

l = √(r² + h²)

l = √(15² + 20²)

l = √(225 + 400)

l = √625

l = 25 inches

Therefore, the slant height of this cone = 25 inches

3 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
oksian1 [2.3K]

Answer:

17 seconds

Step-by-step explanation:

Solution:-

The trajectory of a rocket launched is modeled by a parabolic path via a quadratic equation as follows:

                               y = -16x^2 + 266x +102

Where,

                   y: The height of the rocket from ground

                   x: The time taken since rocket launch

We are to determine the time ( x ) it takes for the rocket to hit the ground. This can be determined by setting the quantity ( y ) to zero as follows

                             y = -16x^2 + 266x +102 = 0\\\\ -16x^2 + 266x +102 = 0

solve the quadratic equation using quadratic formula as follows:

                             x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-266 +/- \sqrt{266^2 - 4*(-16)*(102)} }{2*(-16)} \\\\x = \frac{-266 +/- 278 }{-32} \\\\x = 8.3125 +/- 8.6875\\\\x = 17 , -0.375

Answer: Ignore the negative value for time " -0.375 ". Hence, the rocket hits the ground at time t = 17 seconds

6 0
3 years ago
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