Answer:
<em>A</em>(-3, 6), <em>B</em>(-1, -2), <em>C</em>(-7, 1)
Step-by-step explanation:
To the pre-image after a 270°-counterclockwise rotation [90°-clockwise rotation], just reverse it by doing a 270°-clockwise rotation [90°-counterclockwise rotation]:
Extended Rotation Rules
- 270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x)
- 270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)
- 180°-rotation >> (x, y) → (-x, -y)
So, perform your rotation:
270°-clockwise rotation [90°-counterclockwise rotation] → <em>C</em><em>'</em>[1, 7] was originally at <em>C</em>[-7, 1]
→ <em>B'</em>[-2, 1] was originally at <em>B</em>[-1, -2]
→ <em>A</em><em>'</em>[6, 3] was originally at <em>A</em>[-3, 6]
I am joyous to assist you anytime.
When the base and the height of a triangle are the same. the hypotenuse is that number times sqrt2.
B and C are 7, so a would also be 7
16a+1 is the answer to your question
10.5 i’am not sure but I think
