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Serjik [45]
4 years ago
13

A Fruit Stand sells 6 oranges for $3 and 3 grapefruits for $2.40 Lionel buys 10 oranges and 11 grapefruit how much Lionel spend

on the fruit?
Mathematics
2 answers:
lina2011 [118]4 years ago
8 0
$3/6 = .50 per orange
$2.40/3 = .80 per grapefruit

10(.50) + 11(.80) =
$5.00 + $8.80 = $13.80

sdas [7]4 years ago
7 0
Lionel spent $9.50 on oranges and $8.80 on grapefruit. When added together, the total is $18.30. Hope this helped!!
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How u solve 55-[(5*2×3)-5*2]
slava [35]

Answer:

35

Step-by-step explanation:

55-[(5x2x3)-5x2]

55-[30-5x2]

55-20

35

6 0
3 years ago
Find the value of x,y and z. The Diagram is not a scale!
joja [24]

Answer:

x= 76, y = 63  z, 104

Step-by-step explanation:

We can find x since the three angles of a triangle add to 180 degrees

46+58+x = 180

104+x =180

Subtract 104 from each side

x = 180-104

x = 76


x and z form a straight line

x+z =180

76+ z = 180

Subtract 76 from each side

z = 180-76

z = 104


Z, 13 and y make a triangle

z+ 13 +y = 180

104+13+y = 180

117+y=180

Subtract 117 from each side

y = 180-117

y = 63

4 0
3 years ago
Use the compound interest formula to find the compound amount on a $12,000 investment at 5% compounded quarterly for 4 years.
katrin2010 [14]
Total = Principal * [1 + (rate/n)]^n*years
Where "n" is the compounding periods per year
Total = 12,000 * (1+(.05/4))^(4*4)
Total = 12,000 * (1.0125)^(16)
Total = 12,000 *  <span> <span> <span> 1.2198895477 </span> </span> </span> <span> </span>
Total = <span> <span> </span></span><span><span><span>14,638.67</span>


</span> </span>


5 1
4 years ago
Given h(x)=-x-4, solve for x when h(x)=4
Brilliant_brown [7]

Step-by-step explanation:

h(x)=-x-4

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5 0
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What is the sum of the numbers in the series? 15 + 11 + 7 + . . . + (–129)
babymother [125]
Using Gauss's method
Total number of terms = [15-(-129)]/4+1=36+1=37
Add
S=15+11+7+....-125-129
S=-129-125-...+7+11+15
--------------------------------
2S=-114-114-114...(37 times)
=>
sum=S=(1/2)*(-114)*37=-2109


Using AP, T(n)=15+11+7+....-129
T(n)=19-4n  => T(1)=15, T(37)=-129
S(n)=(1/2)(37)(T(1)+T(37)=(1/2)37(15-129)=2109
3 0
3 years ago
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