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Serjik [45]
3 years ago
13

A Fruit Stand sells 6 oranges for $3 and 3 grapefruits for $2.40 Lionel buys 10 oranges and 11 grapefruit how much Lionel spend

on the fruit?
Mathematics
2 answers:
lina2011 [118]3 years ago
8 0
$3/6 = .50 per orange
$2.40/3 = .80 per grapefruit

10(.50) + 11(.80) =
$5.00 + $8.80 = $13.80

sdas [7]3 years ago
7 0
Lionel spent $9.50 on oranges and $8.80 on grapefruit. When added together, the total is $18.30. Hope this helped!!
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Answer:  The required probability of event B is P(B) = 0.37.

Step-by-step explanation:  For two events A and B, we are given the following probabilities :

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From the laws of probability, we have

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\\Rightarrow 0.44=0.34+P(B)-0.27\\\\\Rightarrow 0.44=0.07+P(B)\\\\\Rightarrow P(B)=0.44-0.07\\\\\Rightarrow P(B)=0.37.

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