Let the first and smaller number be x. Since the second number is 5 times the first, the second number is 5x. We also know both of these numbers must add to 50; thus, we can create the following equation.
Combine like terms
Divide both sides by 6
This is the value of the first number. The number you're looking for isn't specified in the question description, so I'll just provide the value of the second number. The second number has to be 5 times the first.
Thus, we just multiply 5 to x.
That's the value of the second number.
Answer:
mention any one contribution of maiti nepal
Answer:
A. {x: x ≥ -4}
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- {Builder Set Notation}
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
3(2x - 1) - 11x ≤ -3x + 5
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Distributive Property Distribute 3: 6x - 3 - 11x ≤ -3x + 5
- [Subtraction] Combine like terms: -5x - 3 ≤ -3x + 5
- [Addition Property of Equality] Add 5x on both sides: -3 ≤ 2x + 5
- [Subtraction Property of Equality] Subtract 5 on both sides: -8 ≤ 2x
- [Division Property of Equality] Divide 2 on both sides: -4 ≤ x
- Rewrite: x ≥ -4
