Use long division to find the quotient below.<br> (x2 + 3x

Which property of addiction does 8+0=8 illustrate

Rus_ich [418]

Answer:

The statement represents the IDENTITY PROPERTY OF ADDITION.

Step-by-step explanation:

Here, the given expression is 8 + 0 = 8

IDENTITY ELEMENT : Identity element is a special type of element in a given set of system, such that any number remains UNALTERED if operated with the identity element.

⇒ a + X = X for, a ≡ IDENTITY ELEMENT

Now, 8 + 0 = 8

Comparing it with the above equation , we get

0 ≡ IDENTITY ELEMENT in the given Binary operation of Addition.

Hence, the statement represent the IDENTITY PROPERTY OF ADDITION.

4 0

2 years ago

How do i complete the rest of the table

Rufina [12.5K]

To find Vanilla for ages 8-12, you add up the known amount from each flavor for that age group and subtract it from the total to get... 50 - (25 + 12) = 13
To find Chocolate for ages 13-17, you add up the amount of people know to pick up late and subtract it from the total amount of people who picked chocolate to get... 100 - (35 + 25) = 40
Now that we have that number, we can use it to find the amount of people ages 13-17 who chose Vanilla. To find this you subtract the total amount of people who chose chocolate and strawberry from the total amount of people to get... 80 - (40 + 12) = 28

This should help :)

4 0

2 years ago

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The temperature, t, in Burrtown starts at 21°F at midnight, when h = 0. For the next few hours, the temperature drops 4 degrees

sweet-ann [11.9K]

In this case the temperature depends on the hour. So temperature is your X and hour is your Y variable. When h=0, x=0. So the 21*C is you x=0 or y-int point.

If we are trying to match the equation for a line of y=mx+b, 21*C=b.

Our rate of change is -4*C/h, which is our m variable.

So y=(-4)x+(21)

OR in this case, t=-4h+21.

Answer D.

6 0

2 years ago

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Need help simple explanation if possible

photoshop1234 [79]

Answer:

m < A = 60º

m < B = 30º

Step-by-step explanation:

The given sides on this triangle are: 6, $6\sqrt{3}$ , and 12

Any triangle with the angles of 30º - 60º - 90º always has side lengths in this proportion:

x, $x\sqrt{3}$ , 2x

We can line this up with the given sides. If x is 6, then 2x would be 12.

x : $x\sqrt{3}$ : 2x = 6 : $6\sqrt{3}$ : 12

Angle B is across from 6, the shortest side. That also means that it corresponds to x, or the smallest angle in the proportion, 30º.

m < B = 30º

Solving for < A:

Method 1) Sum of Angles in a Triangle

Since we already know that one angle is right and therefore 90º and m < B is 30º, we can subtract these from the total sum of angle measures in a triangle to get the last angle, < A.

180º - 90º - 30º = 60º

m < A = 60º

Method 2) Using the second part of the proportion

Since m < A is across from the second largest side, we know that it is equal to $x\sqrt{3}$ ( $6\sqrt{3}$ in this question) or 60º in the angle proportion.

This means that m < A = 60º

Let me know if you have any questions!

4 0

2 years ago

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Determine if each of the following sets is a subspace of Pn, for an appropriate value of n.

snow_tiger [21]

Answer:

1) W₁ is a subspace of Pₙ (R)

2) W₂ is not a subspace of Pₙ (R)

4) W₃ is a subspace of Pₙ (R)

Step-by-step explanation:

Given that;

1.Let W₁ be the set of all polynomials of the form p(t) = at², where a is in R

2.Let W₂ be the set of all polynomials of the form p(t) = t² + a, where a is in R

3.Let W₃ be the set of all polynomials of the form p(t) = at² + at, where a is in R

so

1)

let W₁ = { at² ║ a∈ R }

let ∝ = a₁t² and β = a₂t² ∈W₁

let c₁, c₂ be two scalars

c₁∝ + c₂β = c₁(a₁t²) + c₂(a₂t²)

= c₁a₁t² + c²a₂t²

= (c₁a₁ + c²a₂)t² ∈ W₁

Therefore c₁∝ + c₂β ∈ W₁ for all ∝, β ∈ W₁ and scalars c₁, c₂

Thus, W₁ is a subspace of Pₙ (R)

2)

let W₂ = { t² + a ║ a∈ R }

the zero polynomial 0t² + 0 ∉ W₂

because the coefficient of t² is 0 but not 1

Thus W₂ is not a subspace of Pₙ (R)

3)

let W₃ = { at² + a ║ a∈ R }

let ∝ = a₁t² +a₁t and β = a₂t² + a₂t ∈ W₃

let c₁, c₂ be two scalars

c₁∝ + c₂β = c₁(a₁t² +a₁t) + c₂(a₂t² + a₂t)

= c₁a₁t² +c₁a₁t + c₂a₂t² + c₂a₂t

= (c₁a₁ +c₂a₂)t² + (c₁a₁t + c₂a₂)t ∈ W₃

Therefore c₁∝ + c₂β ∈ W₃ for all ∝, β ∈ W₃ and scalars c₁, c₂

Thus, W₃ is a subspace of Pₙ (R)

8 0

3 years ago

Use long division to find the quotient below. (x2 + 3x - 18) + (x-3)