A role-playing game uses an 11-sided die that displays the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 What is the probability tha
kondor19780726 [428]
Using it's concept, it is found that there is a 27.3% probability that someone throws the 11-sided die one time and rolls a number 9 or higher.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, there are 11 numbers, 3 of which are 9 or higher, hence the probability is:
p = 3/11 = 0.273 = 27.3%.
More can be learned about probabilities at brainly.com/question/14398287
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Answer:
The answer to your question is: y = 3x + 1
Step-by-step explanation:
Data
slope = m = 3
y-intercept = (0, 1)
Formula
(y - y1) = m(x - x1)
(y - 1) = 3(x - 0)
y - 1 = 3x
y = 3x + 1
Answer:
either 5 or 11
Step-by-step explanation:
(8, -12)
(5, -9) or (11, -9)
If y varies consistently with x then it would copy what happens, in a manner of speaking.
In this case, y increases by three, x would either add 3 or subtract 3
I am not completely sure on this.
Answer:
33
Step-by-step explanation:
<u>Step 1: Round to the nearest whole number</u>
If the tenths place, or the number right after the decimal point, is above 5. You add one to the ones place and set the tens place to 0. If the tenths place is below 5, you just set it to 0.
33.091
33
Answer: 33
Answer:
5 x 2 x 2 x 3 x 3
Step-by-step explanation:
