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3 years ago

Indicate a general rule for the nth term of this sequence. -6b, -3b, 0b, 3b, 6b. . .

Mathematics

1 answer:

GREYUIT [131]3 years ago

4 0

Answer:

a(n) = -16b + (n - 1)(3b)

Step-by-step explanation:

First term is -6b.

Common difference is 3b; each new term is equal to the previous one, plus 3b.

Formula for this arithmetic sequence is

a(n) = -16b + (n - 1)(3b)

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Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position

Alenkinab [10]

Answer:

$\cos \theta=-\dfrac{8}{17}$

Step-by-step explanation:

Coordinates of Point b $=(-8,15)$

b lies on the circle whose equation is $x^2+y^2=289$

$x^2+y^2=17^2$

Comparing with the general form a circle with center at the origin: $x^2+y^2=r^2$

The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.

For an angle drawn in standard position through point b,

x=-8 which is negative

y=15 which is positive

Therefore, the angle is in Quadrant II.

$\cos \theta=\dfrac{Adjacent}{Hypotenuse} \\$Adjacent=-8\\Hypotenuse=17\\\cos \theta=\dfrac{-8}{17} \\\cos \theta=-\dfrac{8}{17}$

8 0

3 years ago

Describe how to find the number of 4.00 train tickets you can buy with 32.00

PtichkaEL [24]

Answer:4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Factor completely 5x2 − 5x − 100.

Rama09 [41]

First, factor out 5:
5 (x² -x -20)
We need two numbers that add to -1 and multiply to -20. -5 and 4 satisfy this.
5(x-5)(x+4)

4 0

3 years ago

The age of a father is 3 times the age of his son. 5 years ago, the father was 4

LUCKY_DIMON [66]

Answer:

Step-by-step explanation:

x = father's age

y = son's age

Nowadays:

3x = y

5 years ago:

4(x - 5) = y - 5

4x - 20 = y - 5

4x = y + 15

I hope I've helped you.

3 0

4 years ago

There are 1200 students at a school and 390 of them are boys if each classroom holds 30 students how many classrooms are needed

vodomira [7]

Answer:

40 classrooms

Step-by-step explanation:

Divide 1200 by 30.

1200÷30=40

If 390 students are boys just subtract 390 from 1200.

1200-390= 810

There must be 810 girls if there are 390 boys

5 0

3 years ago