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nadya68 [22]
4 years ago
14

if the second angle is 20% more than the first angle and the third angle is 20% less than the first angle in a triangle, then fi

nd the three angles of the triangle
Mathematics
1 answer:
Mumz [18]4 years ago
3 0

Answer:

Step-by-step explanation:

If the second angle's measure is based on the first angle's measure, and the third angle's measure is also based on the first angle's measure, then the first angle is the main angle. We will call that x.

1st angle: x

2nd angle: x + 20%

3rd angle: x - 20%

By the Triangle Angle-Sum Theorem, all those angles will add up to 180, so:

x + (x + 20%) + (x - 20%) = 180 and

3x = 180 so

x = 60. That means that

2nd angle: 60 + (.2*60) which is

60 + 12 = 72 and

3rd angle: 60 - (.2*60) which is

60 - 12 = 48. Let's check those angles. If

∠1 = 60

∠2 = 72

∠3 = 48,

then ∠1 + ∠2 + ∠3 = 180 and

60 + 72 + 48 does in fact equal 180, so you're done!

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Step-by-step explanation:

8 is you m and 12 is your b

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Are the two graphs functions or not and why or why not
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Answer:

Hi there!

The first one is not a function because it crosses twice using the vertical line test while the second one is a function.

Step-by-step explanation:

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A-lines slope is 7 and its y-intercept is 10 what is the equation of the slope-intercept form?
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Answer: y = 7x + 10

Step-by-step explanation:

Slope-intercept form is: y = mx + b

where m is the slope and b is the y-intercept.

Knowing this, you can plug in your values for the slope and the y-intercept in place of their respective variables. The slope of 7 would replace m and the y-intercept of 10 would replace b to get y = 7x + 10.

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Art's long jump was 3 inches longer than Bill's. Together they jumped 20 feet. How far did they each jump?
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One jumped 13 in and the other jumped 7 in
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3 years ago
A group of physical education majors was discussing the heights of female runners and whether female runners tended to be tall,
Anna11 [10]

Answer:

The 90% confidence interval for the mean µ of the population of female runners.

( 65.0328 , 66.5672)

Step-by-step explanation:

<u>Step(i)</u>

Given  A sample of 12 runners showed a sample mean height of 65.80 inches and a sample standard deviation of 1.95 inches.

Given sample size is n = 12 <30 so small sample

Given sample mean (x⁻) = 65.80 inches

sample standard deviation (S) = 1.95 inches.

<u>Step(ii)</u>

Assume the population is approximately normal.

The 90% confidence interval for the mean µ of the population of female runners.

(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} +t_{\alpha } \frac{S}{\sqrt{n} } )

substitute  all above interval

(65.80 - t_{\alpha } \frac{1.95}{\sqrt{12} } ,65.80 +t_{\alpha } \frac{1.95}{\sqrt{12} } )

The degrees of freedom γ=n-1 = 12-1=11

From t- table = 1.363 at 90 % 0r 0.10 level of significance

(65.80 -1.363 \frac{1.95}{\sqrt{12} } ,65.80 +1.363 \frac{1.95}{\sqrt{12} } )

on calculation , we get

(65.80 -0.7672 ,65.80 + 0.7672)

( 65.0328 , 66.5672)

8 0
3 years ago
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