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Ilya [14]
3 years ago
12

An elephant weighs 15,000 pounds on Earth and 2,500 pounds on the Moon. Assuming the weights are proportional, what percent of i

ts weight on Earth is its weight on the Moon? The elephant’s weight on the Moon is about % of its weight on Earth. Convince Me! How does the percent describe how the weights are related? =·, =·,≈
Mathematics
1 answer:
patriot [66]3 years ago
4 0

Answer:

20,000

Step-by-step explanation:

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3 years ago
3 1/2 - 1 1/3 x x= 1
slamgirl [31]

Answer:

The value of x for the given expression is \frac{15}{8}

Step-by-step explanation:

Given as :

<u>The expression is written </u>

3\dfrac{1}{2} - 1\dfrac{1}{3} × x = 1

Or, 1\dfrac{1}{3} × x = 3\dfrac{1}{2} - 1

Or, \frac{(1\times 3) + 1}{3} × x = \frac{(3\times 2) + 1}{2} - 1

Or, \dfrac{4}{3} × x = \dfrac{7}{2} - 1

Or,  \dfrac{4}{3} × x = \dfrac{7-2}{2}

Or, \dfrac{4}{3} × x = \dfrac{5}{2}

∴ x = \frac{\frac{5}{2}}{\frac{4}{3}}

Or, x = \frac{5\times 3}{2\times 4}

I.e x = \frac{15}{8}

So, The value of x = \frac{15}{8}

Hence The value of x for the given expression is \frac{15}{8} Answer

6 0
3 years ago
Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste
lidiya [134]

Answer:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

For this case we have the following distribution given:

X          3      4       5        6

P(X)   0.07  0.4  0.25  0.28

We can calculate the mean with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74

In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36

And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

3 0
3 years ago
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