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4 years ago

What is 7√27+5√48 in simplified radical form?

1 answer:

3 0

7√27 + 5√48

7 × 3√3 + 5√48

7 × 3√3 + 5 × 4√3

21√3 + 5 × 4√3

21√3 + 20√3

41√3 or 71.014

hope this helps, God bless!

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The equation 8m+3=75 models how many months, m, it takes a tree to reach a height of 75 inches after being potted. If the tree g

DerKrebs [107]

The equation computed simply shows that the number of months will be C. 9 months.

<h3>How to solve the equation</h3>

From the information given, the equation 8m+3=75 models how many months, m, it takes a tree to reach a height of 75 inches after being potted.

Therefore, the number of months will be calculated thus:

8m + 3 = 75

8m = 75 - 3

8m = 72

m = 72/8

m = 9

The correct option is 9 months.

Learn more about equations on:

brainly.com/question/1214333

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3 years ago

SERIOUSLY NEED HELP GOT 10 MINUTES LEFT!! PLS HELP I WILL GIVE BRANLIEST!! AT LEAST COME TAKE A LOOK!!! MY FINAL QUESTIONS!SERIO

meriva

Answer: Divide using synthetic division. If the remainder is 0, then x+2 is a factor.

x+2 is not a factor.

I put your question into a website, I don't know if that will help you but that's the best I can do, I don't even know the answer

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3 years ago

Match the expression on the left with the correct simplified expression on the right.

andriy [413]

Given: The expression below

$\begin{gathered} (\frac{(3x^3y^4)^3}{(3x^2y^2)^2})^2 \\ (\frac{(3x^4y^2)^4}{(3x^5y^2)^3})^2 \end{gathered}$

To Determine: The matching expression to the given expressions

Solution

Let us simplify each of the expressions using exponents rule

$\begin{gathered} Exponent-Rule1=(a^m)^n=a^{m\times n} \\ Exponent-Rule2=(\frac{a^m}{a^n})=a^{m-n} \end{gathered}$

Applying the exponent rule 1 above to the given expressions

$\begin{gathered} (3x^3y^4)^3=3^3x^{3\times3}y^{4\times3}=27x^9y^{12} \\ (3x^2y^2)^2=3^2x^{2\times2}y^{2\times2}=9x^4y^4 \end{gathered}$ $\begin{gathered} (3x^4y^2)^4=3^4x^{4\times4}y^{2\times4}=81x^{16}y^8 \\ (3x^5y^2)^3=3^3x^{5\times3}y^{2\times3}=27x^{15}y^6 \end{gathered}$

Applying the exponent rule 2

$\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}}=\frac{27x^9y^{12}}{9x^4y^4}=\frac{27}{9}x^{9-4}y^{12-4}=3x^5y^8$ $\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}}=\frac{81x^{16}y^8}{27x^{15}y^6}=\frac{81}{27}x^{16-15}y^{8-6}=3xy^2$

Let us not apply exponent rule 1 above

$(\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}})^2=(3x^5y^8)^2=3^2x^{5\times2}y^{8\times2}=9x^{10}y^{16}$ $(\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}})^2=(3xy^2)^2=3^2x^2y^{2\times2}=9x^2y^4$

Hence, the matching is as shown below

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2 years ago

figure a~figure b:figure a r=4 ft figure b r =2 ft v=352 cu ft fing the volume of figure b for a final exam due at midnight, wil

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It would be A. Hiiiii

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3 years ago

Find the measure of angle 5, if m<2 is 120°

Sphinxa [80]

Answer:

Step-by-step explanation:

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3 years ago