It's a right triangle. Use the pythagorean theorem. 36^2+r^2=(r+12)^2. r=48.
No. Since you can only draw from the corners to get triangles, you will end up with two right triangles because of the corners. If it is a right triangle, it can obviously not be obtuse.
Answer:
4x(3x+1)
Step-by-step explanation:
12x^2+4x
apply the exponent rule
=12xx+4x
rewrite 12 as 4*3
=4*3xx+4x
factor out the common term 4x
4x(3x+1)
Answer:
-48.89
Step-by-step explanation:
|5.74 + 2.89| – |16.20 + 41.32
|8.63| – |57.52|
= - 48.89
Answer:
![\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}miles](https://tex.z-dn.net/?f=%5Ctexttt%7BSubmarine%27s%20depth%20relative%20to%20sea%20level%20after%20the%20first%20minute%20%3D%7D-%5Cfrac%7B4%7D%7B15%7Dmiles)
Step-by-step explanation:
Starting at sea level, a submarine descended at a constant rate to a depth of −4/5 mile relative to sea level in 3 minutes.
Total time = 3 minutes
![\texttt{Total depth descended in 3 minutes =}-\frac{4}{5}miles](https://tex.z-dn.net/?f=%5Ctexttt%7BTotal%20depth%20descended%20in%203%20minutes%20%3D%7D-%5Cfrac%7B4%7D%7B5%7Dmiles)
We need to find what was the submarine's depth relative to sea level after the first minute,
![\texttt{Depth descended in per minute =}\frac{-\frac{4}{5}}{3}=-\frac{4}{15}miles](https://tex.z-dn.net/?f=%5Ctexttt%7BDepth%20descended%20in%20per%20minute%20%3D%7D%5Cfrac%7B-%5Cfrac%7B4%7D%7B5%7D%7D%7B3%7D%3D-%5Cfrac%7B4%7D%7B15%7Dmiles)
![\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}\times 1=-\frac{4}{15}miles\\\\\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}miles](https://tex.z-dn.net/?f=%5Ctexttt%7BSubmarine%27s%20depth%20relative%20to%20sea%20level%20after%20the%20first%20minute%20%3D%7D-%5Cfrac%7B4%7D%7B15%7D%5Ctimes%201%3D-%5Cfrac%7B4%7D%7B15%7Dmiles%5C%5C%5C%5C%5Ctexttt%7BSubmarine%27s%20depth%20relative%20to%20sea%20level%20after%20the%20first%20minute%20%3D%7D-%5Cfrac%7B4%7D%7B15%7Dmiles)