Answer:
<u>Option: a</u> is correct.
Limit of the function at x=2 is: 2
Step-by-step explanation:
Clearly by looking at the graph of the function we could observe that the function f(x) is defined as:
f(x)= -x+4 when x≠4
and 8 when x=2
since we could see that the function f(x) is a line segment that passes through the point (4,0) and (0,4).
and the equation of line passing through two points (a,b) and (c,d) is given by:
![y-b=\dfrac{d-b}{c-a}\times (x-a)](https://tex.z-dn.net/?f=y-b%3D%5Cdfrac%7Bd-b%7D%7Bc-a%7D%5Ctimes%20%28x-a%29)
Here a,b)=(4,0) and (c,d)=(0,4)
Hence,
the equation of line is:
![y-0=\dfrac{4-0}{0-4}\times (x-4)\\\\y=\dfrac{4}{-4}\tmes (x-4)\\\\y=-1(x-4)\\\\y=-x+4](https://tex.z-dn.net/?f=y-0%3D%5Cdfrac%7B4-0%7D%7B0-4%7D%5Ctimes%20%28x-4%29%5C%5C%5C%5Cy%3D%5Cdfrac%7B4%7D%7B-4%7D%5Ctmes%20%28x-4%29%5C%5C%5C%5Cy%3D-1%28x-4%29%5C%5C%5C%5Cy%3D-x%2B4)
Now the left hand limit of the function at x=2 is:
![\lim_{h \to 0} f(2-h)\\\\= \lim_{h \to 0} -(2-h)+4\\ \\=\lim_{h \to 0} -2+h+4\\\\=\lim_{h \to 0}2+h\\\\=2](https://tex.z-dn.net/?f=%5Clim_%7Bh%20%5Cto%200%7D%20f%282-h%29%5C%5C%5C%5C%3D%20%5Clim_%7Bh%20%5Cto%200%7D%20-%282-h%29%2B4%5C%5C%20%5C%5C%3D%5Clim_%7Bh%20%5Cto%200%7D%20-2%2Bh%2B4%5C%5C%5C%5C%3D%5Clim_%7Bh%20%5Cto%200%7D2%2Bh%5C%5C%5C%5C%3D2)
Similarly the right hand limit of the function at x=2 is:
![\lim_{h \to 0} f(2+h)\\\\= \lim_{h \to 0} -(2+h)+4\\ \\=\lim_{h \to 0} -2-h+4\\\\=\lim_{h \to 0}2-h\\\\=2](https://tex.z-dn.net/?f=%5Clim_%7Bh%20%5Cto%200%7D%20f%282%2Bh%29%5C%5C%5C%5C%3D%20%5Clim_%7Bh%20%5Cto%200%7D%20-%282%2Bh%29%2B4%5C%5C%20%5C%5C%3D%5Clim_%7Bh%20%5Cto%200%7D%20-2-h%2B4%5C%5C%5C%5C%3D%5Clim_%7Bh%20%5Cto%200%7D2-h%5C%5C%5C%5C%3D2)
Hence, the limit of the function at x=2 is:
2