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3 years ago

Someone help me with these math problems please Please

Mathematics

2 answers:

Kazeer [188]3 years ago

8 0

Answer:

a=15 26.1 + b =54.6

Step-by-step explanation:

for the second question we first multiply 8.7 by 3 which gives us 26.1 and since there is only one answer with 26.1 it's it.

Montano1993 [528]3 years ago

7 0

Answer:

a = 15

34.8 + b = 54.6

Step-by-step explanation:

First one:

5a - 10b = 45 (b = 3)

5a - 10(3) = 45

5a - 30 = 45

5a = 75

a = 15

Second one

b + a + 3a = 54.6

b + 4a = 54.6 ( a = 8.7)

b + 4(8.7) = 54.6

b + 34.8 = 54.6

34.8 + b = 54.6

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I round to 900 I have twice as many hundreds as ones and all my digits are different but their sums are 18 can someone answer th

stellarik [79]

Answer:

The number of once is 9.1

The number of hundreds is 8.9

Step-by-step explanation:

Given as :

The total of digits having ones and hundreds = 900

The sum of digits = 18

Let The number of ones digit = O

And The number of hundreds digit = H

So, According to question

H + O = 18 .........1

100 × H + 1 × O = 900 ........2

Solving the equation

( 100 × H - H ) + ( O - O ) = 900 - 18

Or, 99 H + 0 = 882

Or , 99 H = 882

∴ H = $\frac{882}{99}$

I.e H = 8.9

Put the value of H in eq 1

So, O = 18 - H

I.e O = 18 - 8.9

∴ O = 9.1

So, number of once = 9.1

number of hundreds = 8.9

Hence The number of once is 9.1 and The number of hundreds is 8.9

Answer

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3 years ago

Judy is looking to buy a textbook. The book normally costs $75.82, but it is on sale for 35% below

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Answer:

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Step-by-step explanation:

0.35 x 75.82 = 26.537

75.82 - 26.537

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2 years ago

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