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geniusboy [140]
3 years ago
7

P16 Consider the following network. ISP B provides national backbone service to regional ISP A. ISP C provides national backbone

service to regional ISP D. Each ISP consists of one AS. B and C peer with each other in two places using BGP. Consider traffic going from A to D. B would prefer to hand that traffic over to C on the West Coast (so that C would have to absorb the cost of carrying the traffic cross-country), while C would prefer to get the traffic via its East Coast peering point with B (so that B would have carried the traffic across the country). What BGP mechanism might C use, so that B would hand over A-to-D traffic at its East Coast peering point?
Computers and Technology
1 answer:
Art [367]3 years ago
7 0

Solution :

Considering the following data :

$\text{ISP B}$ provides the national backbone to the regional $\text{ISP A}$.

$\text{ISP C}$ provides the national backbone to the regional $\text{ISP D}$.

Each of the ISP consists of one autonomous systems (AS).

$\text{ISP B}$ would like to hand over the traffic of C through the $\text{West}$ Coast.

The $\text{ISP C}$ would like to receive traffic from B's peering point via East Coast.

One way for $C$ to force $B$ to hand over all of $B$’s traffic to $D$ on the east coast is for $C$ to  only advertise its route to $D$ via its east coast peering point with $C$.

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Answer:

  1. import java.util.Arrays;
  2. public class Main {
  3.    public static void main(String[] args) {
  4.        String [] first = {"David", "Mike", "Katie", "Lucy"};
  5.        String [] middle = {"A", "B", "C", "D"};
  6.        String [] names = makeNames(first, middle);
  7.        System.out.println(Arrays.toString(names));
  8.    }
  9.    public static String [] makeNames(String [] array1, String [] array2){
  10.           if(array1.length == 0){
  11.               return array1;
  12.           }
  13.           if(array2.length == 0){
  14.               return array2;
  15.           }
  16.           String [] newNames = new String[array1.length];
  17.           for(int i=0; i < array1.length; i++){
  18.               newNames[i] = array1[i] + " " + array2[i];
  19.           }
  20.           return newNames;
  21.    }
  22. }

Explanation:

The solution code is written in Java.

Firstly, create the makeNames method by following the method signature as required by the question (Line 12). Check if any one the input string array is with size 0, return the another string array (Line 14 - 20). Else, create a string array, newNames (Line 22). Use a for loop to repeatedly concatenate the string from array1 with a single space " " and followed with the string from array2 and set it as item of the newNames array (Line 24-26). Lastly, return the newNames array (Line 28).

In the main program create two string array, first and middle, and pass the two arrays to the makeNames methods as arguments (Line 5-6). The returned array is assigned to names array (Line 7). Display the names array to terminal (Line 9) and we shall get the sample output: [David A, Mike B, Katie C, Lucy D]

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The complete solution is attached below.

The In-House solutions' hierarchical diagram covers four categories, including product, service, training, support, and about.

Learn more about Hierarchical drawing here:

brainly.com/question/26031625

#SPJ1

 

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