Answer:
Nothing will be printed
Explanation:
You can easily find out that FL is not a member of the Dictionary. And we are checking these in the if. Since the if condition ends up being false, the further process will not run as they will only if the condition ends up being true. Hence, nothing will be printed.
Remember, del is used to delete a dictionary item. If this would have been a true condition for if then the FL item in the dictionary would have been deleted as it, in that case, would have been present there. And then the next line would have again added the FL item, and print would have printed the dictionary items with FL item as well. However, since if the condition is ending up being false, nothing will be printed.
If cities['FL'] and print is outside if then
the output will be
{'FL': 'Tallahassee', 'GA': 'Atlanta', 'NY': 'Albany', 'CA': 'San Diego'}
Answer:third stage of parent-infant attachment
Explanation:
Answer:
The output streams to this question is "output.print(message)".
Explanation:
The description of the following can be given as:
- In the given question it is define a string datatype variable that is "message".
- Then we create a reference variable of PrintWriter class that is "output" and call string type variable that is message by the use of the print function we print message.
Explanation:
The first 3 lines of code tell the user to input a 5 digit number (ex. 72,910) or a 1 digit number (ex. 3). The next 5 lines of code determine if it is a 5/1 digit number or not. If it is, it prints "Success!". The rest of the code just tells that if it's not a 5/1 digit number, and if it's not, it gives errors and tells the user to try again.
Hope this helps!
Answer:
/ declare the necessary header files.
#include <iostream>
#include <string>
#include <vector>
using namespace std;
// declare the main function.
int main()
{
// declare a vector.
vector<string> words;
vector<int> counts;
// declare variables.
int size;
string str;
cin >> size;
// start the for loop.
for(int i = 0; i < size; ++i)
{
// input string.
cin >> str;
words.push_back(str);
}
// start the for loop.
for(int i = 0; i < size; ++i)
{
int count = 0;
// start the for loop.
for(int j = 0; j < words.size(); ++j)
{
// check the condition.
if(words[j] == words[i])
{
count++;
}
}
counts.push_back(count);
}
// start the for loop.
for(int i = 0; i < size; ++i)
{
// display result on console.
cout << words[i] << "\t" << counts[i] << endl;
}
return 0;
}
Explanation: